Boaz Shuster abc5bcad87 Fix the create API when fromSrc has a bad URL ...

When sending a bad URL in the fromSrc parameter using cURL
the response will have status code 200 while it should have 404
or 500 (depends on the error).

This commit addresses this problem in the following ways:
 * Before, `src` was parsed using url.Parse and if the
   returned `url.Scheme` was empty it was set to 'http'
   and `url.Host` was set to `src`.
   This is bad because if `src` was 'web.com/tars/image1.tar'
   The `url.String()` returns 'web.com%2Ftars%2Fimage1.tar`
   which will cause the daemon to fail downloading the file
 * Before writing the "Downloading" message, the image
   is attempted to be downloaded and if there is no error
   the "Downloading" message is sent.

Signed-off-by: Boaz Shuster <ripcurld.github@gmail.com>
Upstream-commit: e050f1760dd8a3d48d95bb3d2de503fc4177ff5f
Component: engine

2017-03-26 15:21:13 +03:00

components/engine

Fix the create API when fromSrc has a bad URL

2017-03-26 15:21:13 +03:00

Description

Интерфейс командной строки Docker

318 MiB

Languages

Go 92%

Shell 5.5%

Dockerfile 1.1%

Go-Checksums 0.9%

Makefile 0.3%

Other 0.2%