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Undo faulty attempt at not relying on RINFO_IS_PUSHED_DOWN.
I've had a bee in my bonnet for some time about getting rid of RestrictInfo.is_pushed_down, because it's squishily defined and requires not-inexpensive extra tests to use (cf RINFO_IS_PUSHED_DOWN). In commit 2489d76c4, I tried to make remove_rel_from_query() not depend on that macro; but the replacement test is buggy, as exposed by a report from Rushabh Lathia and Robert Haas. That change was pretty incidental to the main goal of 2489d76c4, so let's just revert it for now. (Getting rid of is_pushed_down is still far away, anyway.) Discussion: https://postgr.es/m/CA+TgmoYco=hmg+iX1CW9Y1_CzNoSL81J03wUG-d2_3=rue+L2A@mail.gmail.com
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@ -466,12 +466,7 @@ remove_rel_from_query(PlannerInfo *root, int relid, int ojrelid,
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remove_join_clause_from_rels(root, rinfo, rinfo->required_relids);
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/*
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* If the qual lists ojrelid in its required_relids, it must have come
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* from above the outer join we're removing (so we need to keep it);
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* if it does not, then it didn't and we can discard it.
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*/
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if (bms_is_member(ojrelid, rinfo->required_relids))
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if (RINFO_IS_PUSHED_DOWN(rinfo, joinrelids))
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{
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/*
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* There might be references to relid or ojrelid in the
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@ -5320,6 +5320,22 @@ select 1 from (select a.id FROM a left join b on a.b_id = b.id) q,
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Filter: (a.id = i)
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(4 rows)
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-- check join removal within RHS of an outer join
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explain (costs off)
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select c.id, ss.a from c
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left join (select d.a from onerow, d left join b on d.a = b.id) ss
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on c.id = ss.a;
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QUERY PLAN
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--------------------------------
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Hash Right Join
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Hash Cond: (d.a = c.id)
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-> Nested Loop
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-> Seq Scan on onerow
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-> Seq Scan on d
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-> Hash
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-> Seq Scan on c
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(7 rows)
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CREATE TEMP TABLE parted_b (id int PRIMARY KEY) partition by range(id);
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CREATE TEMP TABLE parted_b1 partition of parted_b for values from (0) to (10);
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-- test join removals on a partitioned table
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@ -1927,6 +1927,12 @@ explain (costs off)
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select 1 from (select a.id FROM a left join b on a.b_id = b.id) q,
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lateral generate_series(1, q.id) gs(i) where q.id = gs.i;
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-- check join removal within RHS of an outer join
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explain (costs off)
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select c.id, ss.a from c
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left join (select d.a from onerow, d left join b on d.a = b.id) ss
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on c.id = ss.a;
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CREATE TEMP TABLE parted_b (id int PRIMARY KEY) partition by range(id);
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CREATE TEMP TABLE parted_b1 partition of parted_b for values from (0) to (10);
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