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Fix progress logging when scale factor is large.
Integer overflow showed minus percent and minus remaining time something like this. 239300000 of 3800000000 tuples (-48%) done (elapsed 226.86 s, remaining -696.10 s).
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108e3992cd
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@ -1720,11 +1720,11 @@ init(bool is_no_vacuum)
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INSTR_TIME_SUBTRACT(diff, start);
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elapsed_sec = INSTR_TIME_GET_DOUBLE(diff);
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remaining_sec = (scale * naccounts - j) * elapsed_sec / j;
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remaining_sec = ((double) scale * naccounts - j) * elapsed_sec / j;
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fprintf(stderr, INT64_FORMAT " of " INT64_FORMAT " tuples (%d%%) done (elapsed %.2f s, remaining %.2f s).\n",
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j, (int64) naccounts * scale,
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(int) (((int64) j * 100) / (naccounts * scale)),
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(int) (((int64) j * 100) / (naccounts * (int64) scale)),
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elapsed_sec, remaining_sec);
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}
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/* let's not call the timing for each row, but only each 100 rows */
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@ -1734,14 +1734,14 @@ init(bool is_no_vacuum)
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INSTR_TIME_SUBTRACT(diff, start);
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elapsed_sec = INSTR_TIME_GET_DOUBLE(diff);
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remaining_sec = (scale * naccounts - j) * elapsed_sec / j;
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remaining_sec = ((double) scale * naccounts - j) * elapsed_sec / j;
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/* have we reached the next interval (or end)? */
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if ((j == scale * naccounts) || (elapsed_sec >= log_interval * LOG_STEP_SECONDS))
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{
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fprintf(stderr, INT64_FORMAT " of " INT64_FORMAT " tuples (%d%%) done (elapsed %.2f s, remaining %.2f s).\n",
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j, (int64) naccounts * scale,
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(int) (((int64) j * 100) / (naccounts * scale)), elapsed_sec, remaining_sec);
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(int) (((int64) j * 100) / (naccounts * (int64) scale)), elapsed_sec, remaining_sec);
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/* skip to the next interval */
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log_interval = (int) ceil(elapsed_sec / LOG_STEP_SECONDS);
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