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hide RoomSubList if has 0 tiles and either searchFilter or emptyContent
Signed-off-by: Michael Telatynski <7t3chguy@gmail.com>
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@@ -1,6 +1,7 @@
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/*
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/*
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Copyright 2017 Vector Creations Ltd
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Copyright 2015, 2016 OpenMarket Ltd
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Copyright 2015, 2016 OpenMarket Ltd
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Copyright 2017 Vector Creations Ltd
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Copyright 2018 New Vector Ltd
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Licensed under the Apache License, Version 2.0 (the "License");
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Licensed under the Apache License, Version 2.0 (the "License");
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you may not use this file except in compliance with the License.
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you may not use this file except in compliance with the License.
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@@ -349,8 +350,14 @@ var RoomSubList = React.createClass({
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var label = this.props.collapsed ? null : this.props.label;
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var label = this.props.collapsed ? null : this.props.label;
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let content;
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let content;
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if (this.state.sortedList.length === 0 && !this.props.searchFilter && this.props.extraTiles.length === 0) {
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if (this.state.sortedList.length === 0 && this.props.extraTiles.length === 0) {
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content = this.props.emptyContent;
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// if no search filter is applied and there is a placeholder defined then show it, otherwise show nothing
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if (!this.props.searchFilter && this.props.emptyContent) {
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content = this.props.emptyContent;
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} else {
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// don't show an empty sublist
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return null;
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}
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} else {
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} else {
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content = this.makeRoomTiles();
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content = this.makeRoomTiles();
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content.push(...this.props.extraTiles);
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content.push(...this.props.extraTiles);
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