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Don't Block Removing File on Being Able to Read It
`open()`'s mode bits are only applied to files that are created by the call. If the output file already exists, but is not readable, the `fopen()` would fail, preventing us from removing it, which would mean that the file would not end up with the correct permission bits. It's not clear to me why the `fopen()` is there at all. `UTIL_isRegularFile()` should be sufficient, AFAICT.
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@@ -669,7 +669,6 @@ FIO_openDstFile(FIO_ctx_t* fCtx, FIO_prefs_t* const prefs,
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if (UTIL_isRegularFile(dstFileName)) {
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/* Check if destination file already exists */
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FILE* const fCheck = fopen( dstFileName, "rb" );
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#if !defined(_WIN32)
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/* this test does not work on Windows :
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* `NUL` and `nul` are detected as regular files */
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@@ -678,8 +677,6 @@ FIO_openDstFile(FIO_ctx_t* fCtx, FIO_prefs_t* const prefs,
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dstFileName);
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}
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#endif
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if (fCheck != NULL) { /* dst file exists, authorization prompt */
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fclose(fCheck);
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if (!prefs->overwrite) {
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if (g_display_prefs.displayLevel <= 1) {
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/* No interaction possible */
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@@ -693,7 +690,7 @@ FIO_openDstFile(FIO_ctx_t* fCtx, FIO_prefs_t* const prefs,
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}
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/* need to unlink */
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FIO_removeFile(dstFileName);
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} }
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}
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{ const int fd = open(dstFileName, O_WRONLY|O_CREAT|O_TRUNC, mode);
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FILE* f = NULL;
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@@ -513,6 +513,21 @@ if [ "$isWindows" = false ] ; then
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rm -f tmp1.zst tmp2.zst tmp1.out tmp2.out
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println "test : check permissions on pre-existing output file in compression "
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chmod 0600 tmp1
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touch tmp1.zst
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chmod 0400 tmp1.zst
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zstd -f tmp1 -o tmp1.zst
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assertFilePermissions tmp1.zst 600
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println "test : check permissions on pre-existing output file in decompression "
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chmod 0400 tmp1.zst
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touch tmp1.out
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chmod 0200 tmp1.out
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zstd -f -d tmp1.zst -o tmp1.out
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assertFilePermissions tmp1.out 400
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rm -f tmp1.zst tmp1.out
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umask 0666
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chmod 0666 tmp1 tmp2
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