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Grammar in comments
Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
This commit is contained in:
@ -5672,7 +5672,7 @@ static psa_status_t psa_key_derivation_start_hmac(
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* It isn't enough to require the caller to initialize operation to
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* It isn't enough to require the caller to initialize operation to
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* PSA_MAC_OPERATION_INIT, since one field is a union and initializing
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* PSA_MAC_OPERATION_INIT, since one field is a union and initializing
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* a union does not necessarily initialize all of its members.
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* a union does not necessarily initialize all of its members.
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* psa_mac_setup() would could handle PSA_MAC_OPERATION_INIT, but here we
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* psa_mac_setup() would handle PSA_MAC_OPERATION_INIT, but here we
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* bypass it and call lower-level functions directly. */
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* bypass it and call lower-level functions directly. */
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memset(operation, 0, sizeof(*operation));
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memset(operation, 0, sizeof(*operation));
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@ -465,7 +465,7 @@ psa_status_t mbedtls_psa_mac_compute(
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{
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{
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psa_status_t status = PSA_ERROR_CORRUPTION_DETECTED;
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psa_status_t status = PSA_ERROR_CORRUPTION_DETECTED;
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mbedtls_psa_mac_operation_t operation = MBEDTLS_PSA_MAC_OPERATION_INIT;
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mbedtls_psa_mac_operation_t operation = MBEDTLS_PSA_MAC_OPERATION_INIT;
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/* Make sure the whole the operation is zeroed.
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/* Make sure the whole operation is zeroed.
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* PSA_MAC_OPERATION_INIT does not necessarily do it fully,
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* PSA_MAC_OPERATION_INIT does not necessarily do it fully,
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* since one field is a union and initializing a union does not
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* since one field is a union and initializing a union does not
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* necessarily initialize all of its members.
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* necessarily initialize all of its members.
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