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mirror of https://github.com/Mbed-TLS/mbedtls.git synced 2025-07-29 11:41:15 +03:00

Merge pull request #4611 from gilles-peskine-arm/random-range-uniformity-3.0

Fix non-uniform random generation in a range
This commit is contained in:
Manuel Pégourié-Gonnard
2021-06-04 10:43:15 +02:00
committed by GitHub
19 changed files with 1039 additions and 261 deletions

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@ -871,6 +871,44 @@ int mbedtls_mpi_fill_random( mbedtls_mpi *X, size_t size,
int (*f_rng)(void *, unsigned char *, size_t),
void *p_rng );
/** Generate a random number uniformly in a range.
*
* This function generates a random number between \p min inclusive and
* \p N exclusive.
*
* The procedure complies with RFC 6979 §3.3 (deterministic ECDSA)
* when the RNG is a suitably parametrized instance of HMAC_DRBG
* and \p min is \c 1.
*
* \note There are `N - min` possible outputs. The lower bound
* \p min can be reached, but the upper bound \p N cannot.
*
* \param X The destination MPI. This must point to an initialized MPI.
* \param min The minimum value to return.
* It must be nonnegative.
* \param N The upper bound of the range, exclusive.
* In other words, this is one plus the maximum value to return.
* \p N must be strictly larger than \p min.
* \param f_rng The RNG function to use. This must not be \c NULL.
* \param p_rng The RNG parameter to be passed to \p f_rng.
*
* \return \c 0 if successful.
* \return #MBEDTLS_ERR_MPI_ALLOC_FAILED if a memory allocation failed.
* \return #MBEDTLS_ERR_MPI_BAD_INPUT_DATA if \p min or \p N is invalid
* or if they are incompatible.
* \return #MBEDTLS_ERR_MPI_NOT_ACCEPTABLE if the implementation was
* unable to find a suitable value within a limited number
* of attempts. This has a negligible probability if \p N
* is significantly larger than \p min, which is the case
* for all usual cryptographic applications.
* \return Another negative error code on failure.
*/
int mbedtls_mpi_random( mbedtls_mpi *X,
mbedtls_mpi_sint min,
const mbedtls_mpi *N,
int (*f_rng)(void *, unsigned char *, size_t),
void *p_rng );
/**
* \brief Compute the greatest common divisor: G = gcd(A, B)
*