mirror of
				https://sourceware.org/git/glibc.git
				synced 2025-11-02 09:33:31 +03:00 
			
		
		
		
	
		
			
				
	
	
		
			71 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			71 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/* Return basename of given pathname according to the weird XPG specification.
 | 
						|
   Copyright (C) 1997-2025 Free Software Foundation, Inc.
 | 
						|
   This file is part of the GNU C Library.
 | 
						|
 | 
						|
   The GNU C Library is free software; you can redistribute it and/or
 | 
						|
   modify it under the terms of the GNU Lesser General Public
 | 
						|
   License as published by the Free Software Foundation; either
 | 
						|
   version 2.1 of the License, or (at your option) any later version.
 | 
						|
 | 
						|
   The GNU C Library is distributed in the hope that it will be useful,
 | 
						|
   but WITHOUT ANY WARRANTY; without even the implied warranty of
 | 
						|
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
 | 
						|
   Lesser General Public License for more details.
 | 
						|
 | 
						|
   You should have received a copy of the GNU Lesser General Public
 | 
						|
   License along with the GNU C Library; if not, see
 | 
						|
   <https://www.gnu.org/licenses/>.  */
 | 
						|
 | 
						|
#include <string.h>
 | 
						|
#include <libgen.h>
 | 
						|
 | 
						|
 | 
						|
char *
 | 
						|
__xpg_basename (char *filename)
 | 
						|
{
 | 
						|
  char *p;
 | 
						|
 | 
						|
  if (filename == NULL || filename[0] == '\0')
 | 
						|
    /* We return a pointer to a static string containing ".".  */
 | 
						|
    p = (char *) ".";
 | 
						|
  else
 | 
						|
    {
 | 
						|
      p = strrchr (filename, '/');
 | 
						|
 | 
						|
      if (p == NULL)
 | 
						|
	/* There is no slash in the filename.  Return the whole string.  */
 | 
						|
	p = filename;
 | 
						|
      else
 | 
						|
	{
 | 
						|
	  if (p[1] == '\0')
 | 
						|
	    {
 | 
						|
	      /* We must remove trailing '/'.  */
 | 
						|
	      while (p > filename && p[-1] == '/')
 | 
						|
		--p;
 | 
						|
 | 
						|
	      /* Now we can be in two situations:
 | 
						|
		 a) the string only contains '/' characters, so we return
 | 
						|
		    '/'
 | 
						|
		 b) p points past the last component, but we have to remove
 | 
						|
		    the trailing slash.  */
 | 
						|
	      if (p > filename)
 | 
						|
		{
 | 
						|
		  *p-- = '\0';
 | 
						|
		  while (p > filename && p[-1] != '/')
 | 
						|
		    --p;
 | 
						|
		}
 | 
						|
	      else
 | 
						|
		/* The last slash we already found is the right position
 | 
						|
		   to return.  */
 | 
						|
		while (p[1] != '\0')
 | 
						|
		  ++p;
 | 
						|
	    }
 | 
						|
	  else
 | 
						|
	    /* Go to the first character of the name.  */
 | 
						|
	    ++p;
 | 
						|
	}
 | 
						|
    }
 | 
						|
 | 
						|
  return p;
 | 
						|
}
 |