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			106 lines
		
	
	
		
			3.4 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			106 lines
		
	
	
		
			3.4 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /* Copyright (C) 1991-2015 Free Software Foundation, Inc.
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|    This file is part of the GNU C Library.
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|    Written by Torbjorn Granlund (tege@sics.se),
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|    with help from Dan Sahlin (dan@sics.se);
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|    commentary by Jim Blandy (jimb@ai.mit.edu).
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| 
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|    The GNU C Library is free software; you can redistribute it and/or
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|    modify it under the terms of the GNU Lesser General Public
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|    License as published by the Free Software Foundation; either
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|    version 2.1 of the License, or (at your option) any later version.
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| 
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|    The GNU C Library is distributed in the hope that it will be useful,
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|    but WITHOUT ANY WARRANTY; without even the implied warranty of
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|    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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|    Lesser General Public License for more details.
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| 
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|    You should have received a copy of the GNU Lesser General Public
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|    License along with the GNU C Library; if not, see
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|    <http://www.gnu.org/licenses/>.  */
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| 
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| #include <string.h>
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| #include <stdlib.h>
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| 
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| #undef strlen
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| 
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| /* Return the length of the null-terminated string STR.  Scan for
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|    the null terminator quickly by testing four bytes at a time.  */
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| size_t
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| strlen (const char *str)
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| {
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|   const char *char_ptr;
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|   const unsigned long int *longword_ptr;
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|   unsigned long int longword, himagic, lomagic;
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| 
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|   /* Handle the first few characters by reading one character at a time.
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|      Do this until CHAR_PTR is aligned on a longword boundary.  */
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|   for (char_ptr = str; ((unsigned long int) char_ptr
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| 			& (sizeof (longword) - 1)) != 0;
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|        ++char_ptr)
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|     if (*char_ptr == '\0')
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|       return char_ptr - str;
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| 
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|   /* All these elucidatory comments refer to 4-byte longwords,
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|      but the theory applies equally well to 8-byte longwords.  */
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| 
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|   longword_ptr = (unsigned long int *) char_ptr;
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| 
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|   /* Bits 31, 24, 16, and 8 of this number are zero.  Call these bits
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|      the "holes."  Note that there is a hole just to the left of
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|      each byte, with an extra at the end:
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| 
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|      bits:  01111110 11111110 11111110 11111111
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|      bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
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| 
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|      The 1-bits make sure that carries propagate to the next 0-bit.
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|      The 0-bits provide holes for carries to fall into.  */
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|   himagic = 0x80808080L;
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|   lomagic = 0x01010101L;
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|   if (sizeof (longword) > 4)
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|     {
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|       /* 64-bit version of the magic.  */
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|       /* Do the shift in two steps to avoid a warning if long has 32 bits.  */
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|       himagic = ((himagic << 16) << 16) | himagic;
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|       lomagic = ((lomagic << 16) << 16) | lomagic;
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|     }
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|   if (sizeof (longword) > 8)
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|     abort ();
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| 
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|   /* Instead of the traditional loop which tests each character,
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|      we will test a longword at a time.  The tricky part is testing
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|      if *any of the four* bytes in the longword in question are zero.  */
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|   for (;;)
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|     {
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|       longword = *longword_ptr++;
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| 
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|       if (((longword - lomagic) & ~longword & himagic) != 0)
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| 	{
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| 	  /* Which of the bytes was the zero?  If none of them were, it was
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| 	     a misfire; continue the search.  */
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| 
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| 	  const char *cp = (const char *) (longword_ptr - 1);
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| 
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| 	  if (cp[0] == 0)
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| 	    return cp - str;
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| 	  if (cp[1] == 0)
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| 	    return cp - str + 1;
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| 	  if (cp[2] == 0)
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| 	    return cp - str + 2;
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| 	  if (cp[3] == 0)
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| 	    return cp - str + 3;
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| 	  if (sizeof (longword) > 4)
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| 	    {
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| 	      if (cp[4] == 0)
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| 		return cp - str + 4;
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| 	      if (cp[5] == 0)
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| 		return cp - str + 5;
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| 	      if (cp[6] == 0)
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| 		return cp - str + 6;
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| 	      if (cp[7] == 0)
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| 		return cp - str + 7;
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| 	    }
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| 	}
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|     }
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| }
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| libc_hidden_builtin_def (strlen)
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