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			72 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			72 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /* Return basename of given pathname according to the weird XPG specification.
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|    Copyright (C) 1997-2014 Free Software Foundation, Inc.
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|    This file is part of the GNU C Library.
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|    Contributed by Ulrich Drepper <drepper@cygnus.com>, 1997.
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| 
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|    The GNU C Library is free software; you can redistribute it and/or
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|    modify it under the terms of the GNU Lesser General Public
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|    License as published by the Free Software Foundation; either
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|    version 2.1 of the License, or (at your option) any later version.
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| 
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|    The GNU C Library is distributed in the hope that it will be useful,
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|    but WITHOUT ANY WARRANTY; without even the implied warranty of
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|    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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|    Lesser General Public License for more details.
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| 
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|    You should have received a copy of the GNU Lesser General Public
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|    License along with the GNU C Library; if not, see
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|    <http://www.gnu.org/licenses/>.  */
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| 
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| #include <string.h>
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| #include <libgen.h>
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| 
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| 
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| char *
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| __xpg_basename (char *filename)
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| {
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|   char *p;
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| 
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|   if (filename == NULL || filename[0] == '\0')
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|     /* We return a pointer to a static string containing ".".  */
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|     p = (char *) ".";
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|   else
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|     {
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|       p = strrchr (filename, '/');
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| 
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|       if (p == NULL)
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| 	/* There is no slash in the filename.  Return the whole string.  */
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| 	p = filename;
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|       else
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| 	{
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| 	  if (p[1] == '\0')
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| 	    {
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| 	      /* We must remove trailing '/'.  */
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| 	      while (p > filename && p[-1] == '/')
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| 		--p;
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| 
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| 	      /* Now we can be in two situations:
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| 		 a) the string only contains '/' characters, so we return
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| 		    '/'
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| 		 b) p points past the last component, but we have to remove
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| 		    the trailing slash.  */
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| 	      if (p > filename)
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| 		{
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| 		  *p-- = '\0';
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| 		  while (p > filename && p[-1] != '/')
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| 		    --p;
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| 		}
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| 	      else
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| 		/* The last slash we already found is the right position
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| 		   to return.  */
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| 		while (p[1] != '\0')
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| 		  ++p;
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| 	    }
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| 	  else
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| 	    /* Go to the first character of the name.  */
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| 	    ++p;
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| 	}
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|     }
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| 
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|   return p;
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| }
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