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			108 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			108 lines
		
	
	
		
			3.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/* Get frequency of the system processor.  powerpc/Linux version.
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   Copyright (C) 2000-2018 Free Software Foundation, Inc.
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   This file is part of the GNU C Library.
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   The GNU C Library is free software; you can redistribute it and/or
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   modify it under the terms of the GNU Lesser General Public
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   License as published by the Free Software Foundation; either
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   version 2.1 of the License, or (at your option) any later version.
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   The GNU C Library is distributed in the hope that it will be useful,
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   but WITHOUT ANY WARRANTY; without even the implied warranty of
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   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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   Lesser General Public License for more details.
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   You should have received a copy of the GNU Lesser General Public
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   License along with the GNU C Library; if not, see
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   <http://www.gnu.org/licenses/>.  */
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#include <ctype.h>
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#include <fcntl.h>
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#include <stdint.h>
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#include <string.h>
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#include <unistd.h>
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#include <sysdep.h>
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#include <libc-vdso.h>
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#include <not-cancel.h>
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hp_timing_t
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__get_clockfreq (void)
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{
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  hp_timing_t result = 0L;
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#ifdef SHARED
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  /* The vDSO does not return an error (it clear cr0.so on returning).  */
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  INTERNAL_SYSCALL_DECL (err);
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  result =
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    INTERNAL_VSYSCALL_NO_SYSCALL_FALLBACK (get_tbfreq, err, uint64_t, 0);
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#else
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  /* We read the information from the /proc filesystem.  /proc/cpuinfo
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     contains at least one line like:
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     timebase        : 33333333
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     We search for this line and convert the number into an integer.  */
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  int fd = __open_nocancel ("/proc/cpuinfo", O_RDONLY);
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  if (__glibc_likely (fd != -1))
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    return result;
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  /* The timebase will be in the 1st 1024 bytes for systems with up
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     to 8 processors.  If the first read returns less then 1024
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     bytes read,  we have the whole cpuinfo and can start the scan.
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     Otherwise we will have to read more to insure we have the
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     timebase value in the scan.  */
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  char buf[1024];
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  ssize_t n;
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  n = __read_nocancel (fd, buf, sizeof (buf));
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  if (n == sizeof (buf))
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    {
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      /* We are here because the 1st read returned exactly sizeof
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         (buf) bytes.  This implies that we are not at EOF and may
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         not have read the timebase value yet.  So we need to read
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         more bytes until we know we have EOF.  We copy the lower
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         half of buf to the upper half and read sizeof (buf)/2
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         bytes into the lower half of buf and repeat until we
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         reach EOF.  We can assume that the timebase will be in
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         the last 512 bytes of cpuinfo, so two 512 byte half_bufs
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         will be sufficient to contain the timebase and will
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         handle the case where the timebase spans the half_buf
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         boundry.  */
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      const ssize_t half_buf = sizeof (buf) / 2;
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      while (n >= half_buf)
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	{
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	  memcpy (buf, buf + half_buf, half_buf);
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	  n = __read_nocancel (fd, buf + half_buf, half_buf);
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	}
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      if (n >= 0)
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	n += half_buf;
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    }
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  __close_nocancel (fd);
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  if (__glibc_likely (n > 0))
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    {
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      char *mhz = memmem (buf, n, "timebase", 7);
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      if (__glibc_likely (mhz != NULL))
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	{
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	  char *endp = buf + n;
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	  /* Search for the beginning of the string.  */
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	  while (mhz < endp && (*mhz < '0' || *mhz > '9') && *mhz != '\n')
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	    ++mhz;
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	  while (mhz < endp && *mhz != '\n')
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	    {
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	      if (*mhz >= '0' && *mhz <= '9')
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		{
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		  result *= 10;
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		  result += *mhz - '0';
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		}
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	      ++mhz;
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	    }
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	}
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    }
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#endif
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  return result;
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}
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