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m68k: Enforce 4-byte alignment on internal locks (BZ #29537)

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A new internal definition, __LIBC_LOCK_ALIGNMENT, is used to force
the 4-byte alignment only for m68k, other architecture keep the
natural alignment of the type used internally (and hppa does not
require 16-byte alignment for kernel-assisted CAS).

Reviewed-by: Florian Weimer <fweimer@redhat.com>
This commit is contained in:
Adhemerval Zanella
2022-08-30 10:33:15 -03:00
parent c75d20b5b2
commit aeb4d2e981
4 changed files with 59 additions and 2 deletions
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8
sysdeps/nptl/libc-lock.h
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@ -22,6 +22,7 @@
#include <pthread.h>
#define __need_NULL
#include <stddef.h>
#include <libc-lock-arch.h>
/* Mutex type. */
@ -29,7 +30,12 @@
# if (!IS_IN (libc) && !IS_IN (libpthread)) || !defined _LIBC
typedef struct { pthread_mutex_t mutex; } __libc_lock_recursive_t;
# else
typedef struct { int lock; int cnt; void *owner; } __libc_lock_recursive_t;
typedef struct
{
int lock __LIBC_LOCK_ALIGNMENT;
int cnt;
void *owner;
} __libc_lock_recursive_t;
# endif
#else
typedef struct __libc_lock_recursive_opaque__ __libc_lock_recursive_t;