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malloc: Use uintptr_t in alloc_buffer

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The values represnt pointers and not sizes. The members of struct
alloc_buffer are already uintptr_t.

Reviewed-by: Florian Weimer <fweimer@redhat.com>
This commit is contained in:
Szabolcs Nagy
2022-03-16 12:09:15 +00:00
parent 3fa20d59d9
commit 68619ddb3b
2 changed files with 8 additions and 8 deletions
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6
malloc/alloc_buffer_alloc_array.c
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@ -23,12 +23,12 @@ void *
__libc_alloc_buffer_alloc_array (struct alloc_buffer *buf, size_t element_size,
size_t align, size_t count)
{
size_t current = buf->__alloc_buffer_current;
uintptr_t current = buf->__alloc_buffer_current;
/* The caller asserts that align is a power of two. */
size_t aligned = ALIGN_UP (current, align);
uintptr_t aligned = ALIGN_UP (current, align);
size_t size;
bool overflow = __builtin_mul_overflow (element_size, count, &size);
size_t new_current = aligned + size;
uintptr_t new_current = aligned + size;
if (!overflow /* Multiplication did not overflow. */
&& aligned >= current /* No overflow in align step. */
&& new_current >= size /* No overflow in size computation. */