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stdio-common: Fix scanf parsing for NaN types [BZ #30647]
The scanf family of functions like sscanf and fscanf currently ignore nan() and nan(n-char-sequence). This happens because __vfscanf_internal only checks for 'nan'. This commit adds support for all valid nan types i.e. nan, nan() and nan(n-char-sequence), where n-char-sequence can be [a-zA-Z0-9_]+, thus fixing the bug 30647. Any other representation of NaN should result in conversion error. New tests are also added to verify the correct parsing of NaN types for float, double and long double formats. Signed-off-by: Avinal Kumar <avinal.xlvii@gmail.com> Reviewed-by: Adhemerval Zanella <adhemerval.zanella@linaro.org>
This commit is contained in:
committed by
Adhemerval Zanella
parent
ac73067cb7
commit
04e8698fcc
@@ -2028,7 +2028,51 @@ digits_extended_fail:
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if (width > 0)
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--width;
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char_buffer_add (&charbuf, c);
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/* It is "nan". */
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/* It is at least "nan". Now we check for nan() and
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nan(n-char-sequence). */
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if (width != 0 && inchar () != EOF)
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{
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if (c == L_('('))
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{
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if (width > 0)
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--width;
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char_buffer_add (&charbuf, c);
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/* A '(' was observed, check for a closing ')', there
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may or may not be a n-char-sequence in between. We
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have to check the longest prefix until there is a
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conversion error or closing parenthesis. */
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do
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{
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if (__glibc_unlikely (width == 0
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|| inchar () == EOF))
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{
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/* Conversion error because we ran out of
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characters. */
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conv_error ();
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break;
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}
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if (!((c >= L_('0') && c <= L_('9'))
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|| (c >= L_('A') && c <= L_('Z'))
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|| (c >= L_('a') && c <= L_('z'))
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|| c == L_('_') || c == L_(')')))
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{
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/* Invalid character was observed. Only valid
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characters are [a-zA-Z0-9_] and ')'. */
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conv_error ();
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break;
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}
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if (width > 0)
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--width;
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char_buffer_add (&charbuf, c);
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}
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while (c != L_(')'));
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/* The loop only exits successfully when ')' is the
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last character. */
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}
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else
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/* It is only 'nan'. */
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ungetc (c, s);
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}
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goto scan_float;
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}
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else if (TOLOWER (c) == L_('i'))
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