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Take care not to modify the sqlite* pointer to sqlite_exec() if we suspect

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that the pointer is stale - that it has previously been passed to
sqlite_close().  Possible fix for ticket #202.  Prior to this fix, test
misuse-5.3 was causing a change to a buffer that had been previously free()-ed. (CVS 799)

FossilOrigin-Name: f04547edfa1643ce52925d317915badfc676bd8b
This commit is contained in:
drh
2002-12-17 13:05:25 +00:00
parent 3e7a609667
commit e7e8bc7739
3 changed files with 18 additions and 12 deletions
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16
src/util.c
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@@ -14,7 +14,7 @@
** This file contains functions for allocating memory, comparing
** strings, and stuff like that.
**
** $Id: util.c,v 1.52 2002/10/20 15:46:23 drh Exp $
** $Id: util.c,v 1.53 2002/12/17 13:05:26 drh Exp $
*/
#include "sqliteInt.h"
#include <stdarg.h>
@@ -1120,16 +1120,22 @@ sqliteLikeCompare(const unsigned char *zPattern, const unsigned char *zString){
** But usually the problem will be seen. The result will be an
** error which can be used to debug the application that is
** using SQLite incorrectly.
**
** Ticket #202: If db->magic is not a valid open value, take care not
** to modify the db structure at all. It could be that db is a stale
** pointer. In other words, it could be that there has been a prior
** call to sqlite_close(db) and db has been deallocated. And we do
** not want to write into deallocated memory.
*/
int sqliteSafetyOn(sqlite *db){
if( db->magic==SQLITE_MAGIC_OPEN ){
db->magic = SQLITE_MAGIC_BUSY;
return 0;
}else{
}else if( db->magic==SQLITE_MAGIC_BUSY || db->magic==SQLITE_MAGIC_ERROR ){
db->magic = SQLITE_MAGIC_ERROR;
db->flags |= SQLITE_Interrupt;
return 1;
}
return 1;
}
/*
@@ -1141,11 +1147,11 @@ int sqliteSafetyOff(sqlite *db){
if( db->magic==SQLITE_MAGIC_BUSY ){
db->magic = SQLITE_MAGIC_OPEN;
return 0;
}else{
}else if( db->magic==SQLITE_MAGIC_OPEN || db->magic==SQLITE_MAGIC_ERROR ){
db->magic = SQLITE_MAGIC_ERROR;
db->flags |= SQLITE_Interrupt;
return 1;
}
return 1;
}
/*