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Fix for ticket #65: If an integer value is too big to be represented as a

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32-bit integer, then treat it as a string. (CVS 611)

FossilOrigin-Name: ad9624798edbd6d0c4652fed3d74fe87498844ff
This commit is contained in:
drh
2002-06-09 01:16:01 +00:00
parent d99f70680f
commit d9e3093038
4 changed files with 41 additions and 11 deletions
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14
src/expr.c
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@@ -12,7 +12,7 @@
** This file contains routines used for analyzing expressions and
** for generating VDBE code that evaluates expressions in SQLite.
**
** $Id: expr.c,v 1.69 2002/06/02 18:22:06 drh Exp $
** $Id: expr.c,v 1.70 2002/06/09 01:16:01 drh Exp $
*/
#include "sqliteInt.h"
#include <ctype.h>
@@ -824,7 +824,17 @@ void sqliteExprCode(Parse *pParse, Expr *pExpr){
break;
}
case TK_INTEGER: {
sqliteVdbeAddOp(v, OP_Integer, atoi(pExpr->token.z), 0);
int iVal = atoi(pExpr->token.z);
char zBuf[30];
sprintf(zBuf,"%d",iVal);
if( strlen(zBuf)!=pExpr->token.n
|| strncmp(pExpr->token.z,zBuf,pExpr->token.n)!=0 ){
/* If the integer value cannot be represented exactly in 32 bits,
** then code it as a string instead. */
sqliteVdbeAddOp(v, OP_String, 0, 0);
}else{
sqliteVdbeAddOp(v, OP_Integer, iVal, 0);
}
sqliteVdbeChangeP3(v, -1, pExpr->token.z, pExpr->token.n);
break;
}