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When the left-hand side of an IN operator is constant and the right-hand

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side is a SELECT, recognize that the IN operator is not constant.
Ticket #1380. (CVS 2624)

FossilOrigin-Name: fc9e04609b6968fc5039a6f9f808aac681f4fc41
This commit is contained in:
drh
2005-08-25 12:45:04 +00:00
parent 65d415cb72
commit 87abf5c033
4 changed files with 40 additions and 10 deletions
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9
src/expr.c
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@@ -12,7 +12,7 @@
** This file contains routines used for analyzing expressions and
** for generating VDBE code that evaluates expressions in SQLite.
**
** $Id: expr.c,v 1.220 2005/08/24 16:54:05 drh Exp $
** $Id: expr.c,v 1.221 2005/08/25 12:45:04 drh Exp $
*/
#include "sqliteInt.h"
#include <ctype.h>
@@ -624,6 +624,8 @@ void sqlite3ExprListDelete(ExprList *pList){
**
** The return value from this routine is 1 to abandon the tree walk
** and 0 to continue.
**
** NOTICE: This routine does *not* descend into subqueries.
*/
static int walkExprList(ExprList *, int (*)(void *, Expr*), void *);
static int walkExprTree(Expr *pExpr, int (*xFunc)(void*,Expr*), void *pArg){
@@ -696,6 +698,11 @@ static int exprNodeIsConstant(void *pArg, Expr *pExpr){
#endif
*((int*)pArg) = 0;
return 2;
case TK_IN:
if( pExpr->pSelect ){
*((int*)pArg) = 0;
return 2;
}
default:
return 0;
}