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Add comments to better explain the two-pass memory allocation approach
for prepared statements. FossilOrigin-Name: 0e5e18ea12c70559d4c63981c0bb5f9430c5bcbb
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@@ -1266,8 +1266,9 @@ void sqlite3VdbeIOTraceSql(Vdbe *p){
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**
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** nByte is the number of bytes of space needed.
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**
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** *ppFrom point to available space and pEnd points to the end of the
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** available space.
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** *ppFrom points to available space and pEnd points to the end of the
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** available space. When space is allocated, *ppFrom is advanced past
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** the end of the allocated space.
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**
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** *pnByte is a counter of the number of bytes of space that have failed
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** to allocate. If there is insufficient space in *ppFrom to satisfy the
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@@ -1348,9 +1349,10 @@ void sqlite3VdbeMakeReady(
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** being called from sqlite3_reset() to reset the virtual machine.
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*/
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if( nVar>=0 && ALWAYS(db->mallocFailed==0) ){
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u8 *zCsr = (u8 *)&p->aOp[p->nOp];
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u8 *zEnd = (u8 *)&p->aOp[p->nOpAlloc];
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int nByte;
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u8 *zCsr = (u8 *)&p->aOp[p->nOp]; /* Memory avaliable for alloation */
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u8 *zEnd = (u8 *)&p->aOp[p->nOpAlloc]; /* First byte past available mem */
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int nByte; /* How much extra memory needed */
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resolveP2Values(p, &nArg);
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p->usesStmtJournal = (u8)usesStmtJournal;
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if( isExplain && nMem<10 ){
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@@ -1360,6 +1362,16 @@ void sqlite3VdbeMakeReady(
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zCsr += (zCsr - (u8*)0)&7;
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assert( EIGHT_BYTE_ALIGNMENT(zCsr) );
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/* Memory for registers, parameters, cursor, etc, is allocated in two
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** passes. On the first pass, we try to reuse unused space at the
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** end of the opcode array. If we are unable to satisfy all memory
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** requirements by reusing the opcode array tail, then the second
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** pass will fill in the rest using a fresh allocation.
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**
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** This two-pass approach that reuses as much memory as possible from
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** the leftover space at the end of the opcode array can significantly
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** reduce the amount of memory held by a prepared statement.
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*/
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do {
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nByte = 0;
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p->aMem = allocSpace(p->aMem, nMem*sizeof(Mem), &zCsr, zEnd, &nByte);
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