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Fix numeric_mul() overflow due to too many digits after decimal point.

This fixes an overflow error when using the numeric * operator if the
result has more than 16383 digits after the decimal point by rounding
the result. Overflow errors should only occur if the result has too
many digits *before* the decimal point.

Discussion: https://postgr.es/m/CAEZATCUmeFWCrq2dNzZpRj5+6LfN85jYiDoqm+ucSXhb9U2TbA@mail.gmail.com
This commit is contained in:
Dean Rasheed
2021-07-10 12:42:59 +01:00
parent 53c38a086a
commit e7fc488ad6
3 changed files with 17 additions and 1 deletions

View File

@ -233,6 +233,7 @@ struct NumericData
*/
#define NUMERIC_DSCALE_MASK 0x3FFF
#define NUMERIC_DSCALE_MAX NUMERIC_DSCALE_MASK
#define NUMERIC_SIGN(n) \
(NUMERIC_IS_SHORT(n) ? \
@ -2958,7 +2959,11 @@ numeric_mul_opt_error(Numeric num1, Numeric num2, bool *have_error)
* Unlike add_var() and sub_var(), mul_var() will round its result. In the
* case of numeric_mul(), which is invoked for the * operator on numerics,
* we request exact representation for the product (rscale = sum(dscale of
* arg1, dscale of arg2)).
* arg1, dscale of arg2)). If the exact result has more digits after the
* decimal point than can be stored in a numeric, we round it. Rounding
* after computing the exact result ensures that the final result is
* correctly rounded (rounding in mul_var() using a truncated product
* would not guarantee this).
*/
init_var_from_num(num1, &arg1);
init_var_from_num(num2, &arg2);
@ -2966,6 +2971,9 @@ numeric_mul_opt_error(Numeric num1, Numeric num2, bool *have_error)
init_var(&result);
mul_var(&arg1, &arg2, &result, arg1.dscale + arg2.dscale);
if (result.dscale > NUMERIC_DSCALE_MAX)
round_var(&result, NUMERIC_DSCALE_MAX);
res = make_result_opt_error(&result, have_error);
free_var(&result);