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Fix conversion of SIMILAR TO regexes for character classes
The code that translates SIMILAR TO pattern matching expressions to POSIX-style regular expressions did not consider that square brackets can be nested. For example, in an expression like [[:alpha:]%_], the logic replaced the placeholders '_' and '%' but it should not. This commit fixes the conversion logic by tracking the nesting level of square brackets marking character class areas, while considering that in expressions like []] or [^]] the first closing square bracket is a regular character. Multiple tests are added to show how the conversions should or should not apply applied while in a character class area, with specific cases added for all the characters converted outside character classes like an opening parenthesis '(', dollar sign '$', etc. Author: Laurenz Albe <laurenz.albe@cybertec.at> Reviewed-by: Tom Lane <tgl@sss.pgh.pa.us> Reviewed-by: Michael Paquier <michael@paquier.xyz> Discussion: https://postgr.es/m/16ab039d1af455652bdf4173402ddda145f2c73b.camel@cybertec.at Backpatch-through: 13
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@ -773,8 +773,11 @@ similar_escape_internal(text *pat_text, text *esc_text)
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int plen,
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elen;
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bool afterescape = false;
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bool incharclass = false;
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int nquotes = 0;
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int charclass_depth = 0; /* Nesting level of character classes,
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* encompassed by square brackets */
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int charclass_start = 0; /* State of the character class start,
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* for carets */
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p = VARDATA_ANY(pat_text);
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plen = VARSIZE_ANY_EXHDR(pat_text);
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@ -904,7 +907,7 @@ similar_escape_internal(text *pat_text, text *esc_text)
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/* fast path */
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if (afterescape)
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{
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if (pchar == '"' && !incharclass) /* escape-double-quote? */
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if (pchar == '"' && charclass_depth < 1) /* escape-double-quote? */
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{
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/* emit appropriate part separator, per notes above */
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if (nquotes == 0)
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@ -953,18 +956,41 @@ similar_escape_internal(text *pat_text, text *esc_text)
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/* SQL escape character; do not send to output */
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afterescape = true;
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}
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else if (incharclass)
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else if (charclass_depth > 0)
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{
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if (pchar == '\\')
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*r++ = '\\';
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*r++ = pchar;
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if (pchar == ']')
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incharclass = false;
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/*
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* Ignore a closing bracket at the start of a character class.
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* Such a bracket is taken literally rather than closing the
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* class. "charclass_start" is 1 right at the beginning of a
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* class and 2 after an initial caret.
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*/
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if (pchar == ']' && charclass_start > 2)
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charclass_depth--;
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else if (pchar == '[')
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charclass_depth++;
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/*
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* If there is a caret right after the opening bracket, it negates
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* the character class, but a following closing bracket should
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* still be treated as a normal character. That holds only for
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* the first caret, so only the values 1 and 2 mean that closing
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* brackets should be taken literally.
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*/
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if (pchar == '^')
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charclass_start++;
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else
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charclass_start = 3; /* definitely past the start */
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}
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else if (pchar == '[')
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{
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/* start of a character class */
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*r++ = pchar;
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incharclass = true;
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charclass_depth++;
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charclass_start = 1;
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}
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else if (pchar == '%')
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{
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