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Rearrange the querytree representation of ORDER BY/GROUP BY/DISTINCT items

as per my recent proposal:

1. Fold SortClause and GroupClause into a single node type SortGroupClause.
We were already relying on them to be struct-equivalent, so using two node
tags wasn't accomplishing much except to get in the way of comparing items
with equal().

2. Add an "eqop" field to SortGroupClause to carry the associated equality
operator.  This is cheap for the parser to get at the same time it's looking
up the sort operator, and storing it eliminates the need for repeated
not-so-cheap lookups during planning.  In future this will also let us
represent GROUP/DISTINCT operations on datatypes that have hash opclasses
but no btree opclasses (ie, they have equality but no natural sort order).
The previous representation simply didn't work for that, since its only
indicator of comparison semantics was a sort operator.

3. Add a hasDistinctOn boolean to struct Query to explicitly record whether
the distinctClause came from DISTINCT or DISTINCT ON.  This allows removing
some complicated and not 100% bulletproof code that attempted to figure
that out from the distinctClause alone.

This patch doesn't in itself create any new capability, but it's necessary
infrastructure for future attempts to use hash-based grouping for DISTINCT
and UNION/INTERSECT/EXCEPT.
This commit is contained in:
Tom Lane
2008-08-02 21:32:01 +00:00
parent 49f001d81e
commit 9511304752
33 changed files with 764 additions and 857 deletions

View File

@ -7,7 +7,7 @@
* Portions Copyright (c) 1994, Regents of the University of California
*
* IDENTIFICATION
* $PostgreSQL: pgsql/src/backend/utils/cache/lsyscache.c,v 1.158 2008/07/30 17:05:04 tgl Exp $
* $PostgreSQL: pgsql/src/backend/utils/cache/lsyscache.c,v 1.159 2008/08/02 21:32:00 tgl Exp $
*
* NOTES
* Eventually, the index information should go through here, too.
@ -254,11 +254,14 @@ get_compare_function_for_ordering_op(Oid opno, Oid *cmpfunc, bool *reverse)
* Get the OID of the datatype-specific btree equality operator
* associated with an ordering operator (a "<" or ">" operator).
*
* If "reverse" isn't NULL, also set *reverse to FALSE if the operator is "<",
* TRUE if it's ">"
*
* Returns InvalidOid if no matching equality operator can be found.
* (This indicates that the operator is not a valid ordering operator.)
*/
Oid
get_equality_op_for_ordering_op(Oid opno)
get_equality_op_for_ordering_op(Oid opno, bool *reverse)
{
Oid result = InvalidOid;
Oid opfamily;
@ -274,6 +277,8 @@ get_equality_op_for_ordering_op(Oid opno)
opcintype,
opcintype,
BTEqualStrategyNumber);
if (reverse)
*reverse = (strategy == BTGreaterStrategyNumber);
}
return result;
@ -666,36 +671,49 @@ get_op_btree_interpretation(Oid opno, List **opfamilies, List **opstrats)
}
/*
* ops_in_same_btree_opfamily
* Return TRUE if there exists a btree opfamily containing both operators.
* (This implies that they have compatible notions of equality.)
* equality_ops_are_compatible
* Return TRUE if the two given equality operators have compatible
* semantics.
*
* This is trivially true if they are the same operator. Otherwise,
* we look to see if they can be found in the same btree or hash opfamily.
* Either finding allows us to assume that they have compatible notions
* of equality. (The reason we need to do these pushups is that one might
* be a cross-type operator; for instance int24eq vs int4eq.)
*/
bool
ops_in_same_btree_opfamily(Oid opno1, Oid opno2)
equality_ops_are_compatible(Oid opno1, Oid opno2)
{
bool result = false;
bool result;
CatCList *catlist;
int i;
/* Easy if they're the same operator */
if (opno1 == opno2)
return true;
/*
* We search through all the pg_amop entries for opno1.
*/
catlist = SearchSysCacheList(AMOPOPID, 1,
ObjectIdGetDatum(opno1),
0, 0, 0);
result = false;
for (i = 0; i < catlist->n_members; i++)
{
HeapTuple op_tuple = &catlist->members[i]->tuple;
Form_pg_amop op_form = (Form_pg_amop) GETSTRUCT(op_tuple);
/* must be btree */
if (op_form->amopmethod != BTREE_AM_OID)
continue;
if (op_in_opfamily(opno2, op_form->amopfamily))
/* must be btree or hash */
if (op_form->amopmethod == BTREE_AM_OID ||
op_form->amopmethod == HASH_AM_OID)
{
result = true;
break;
if (op_in_opfamily(opno2, op_form->amopfamily))
{
result = true;
break;
}
}
}