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Ensure that foreign scans with lateral refs are planned correctly.

As reported in bug #15613 from Srinivasan S A, file_fdw and postgres_fdw
neglected to mark plain baserel foreign paths as parameterized when the
relation has lateral_relids.  Other FDWs have surely copied this mistake,
so rather than just patching those two modules, install a band-aid fix
in create_foreignscan_path to rectify the mistake centrally.

Although the band-aid is enough to fix the visible symptom, correct
the calls in file_fdw and postgres_fdw anyway, so that they are valid
examples for external FDWs.

Also, since the band-aid isn't enough to make this work for parameterized
foreign joins, throw an elog(ERROR) if such a case is passed to
create_foreignscan_path.  This shouldn't pose much of a problem for
existing external FDWs, since it's likely they aren't trying to make such
paths anyway (though some of them may need a defense against joins with
lateral_relids, similar to the one this patch installs into postgres_fdw).

Add some assertions in relnode.c to catch future occurrences of the same
error --- in particular, as backstop against core-code mistakes like the
one fixed by commit bdd9a99aa.

Discussion: https://postgr.es/m/15613-092be1be9576c728@postgresql.org
This commit is contained in:
Tom Lane
2019-02-07 13:10:46 -05:00
parent b33d5e076e
commit 876fd37fc8
6 changed files with 123 additions and 2 deletions

View File

@ -232,6 +232,32 @@ WHERE a.c2 = 6 AND b.c1 = a.c1 AND a.c8 = 'foo' AND b.c7 = upper(a.c7);
SELECT * FROM ft1 WHERE c1 = ANY (ARRAY(SELECT c1 FROM ft2 WHERE c1 < 5));
SELECT * FROM ft2 WHERE c1 = ANY (ARRAY(SELECT c1 FROM ft1 WHERE c1 < 5));
-- bug #15613: bad plan for foreign table scan with lateral reference
EXPLAIN (VERBOSE, COSTS OFF)
SELECT ref_0.c2, subq_1.*
FROM
"S 1"."T 1" AS ref_0,
LATERAL (
SELECT ref_0."C 1" c1, subq_0.*
FROM (SELECT ref_0.c2, ref_1.c3
FROM ft1 AS ref_1) AS subq_0
RIGHT JOIN ft2 AS ref_3 ON (subq_0.c3 = ref_3.c3)
) AS subq_1
WHERE ref_0."C 1" < 10 AND subq_1.c3 = '00001'
ORDER BY ref_0."C 1";
SELECT ref_0.c2, subq_1.*
FROM
"S 1"."T 1" AS ref_0,
LATERAL (
SELECT ref_0."C 1" c1, subq_0.*
FROM (SELECT ref_0.c2, ref_1.c3
FROM ft1 AS ref_1) AS subq_0
RIGHT JOIN ft2 AS ref_3 ON (subq_0.c3 = ref_3.c3)
) AS subq_1
WHERE ref_0."C 1" < 10 AND subq_1.c3 = '00001'
ORDER BY ref_0."C 1";
-- ===================================================================
-- parameterized queries
-- ===================================================================