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remove_rel_from_query() must clean up PlaceHolderVar.phrels fields.
While we got away with this sloppiness before, it's not okay now
that fee7b77b9
caused build_joinrel_tlist() to make use of phrels.
Per report from Robins Tharakan.
Richard Guo (some cosmetic tweaks by me)
Discussion: https://postgr.es/m/CAMbWs4_ngw9sKxpTE8hqk=-ooVX_CQP3DarA4HzkRMz_JKpTrA@mail.gmail.com
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@ -316,12 +316,8 @@ join_is_removable(PlannerInfo *root, SpecialJoinInfo *sjinfo)
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* Remove the target relid from the planner's data structures, having
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* determined that there is no need to include it in the query.
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*
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* We are not terribly thorough here. We must make sure that the rel is
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* no longer treated as a baserel, and that attributes of other baserels
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* are no longer marked as being needed at joins involving this rel.
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* Also, join quals involving the rel have to be removed from the joininfo
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* lists, but only if they belong to the outer join identified by ojrelid
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* and joinrelids.
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* We are not terribly thorough here. We only bother to update parts of
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* the planner's data structures that will actually be consulted later.
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*/
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static void
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remove_rel_from_query(PlannerInfo *root, int relid, int ojrelid,
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@ -429,11 +425,18 @@ remove_rel_from_query(PlannerInfo *root, int relid, int ojrelid,
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}
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else
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{
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PlaceHolderVar *phv = phinfo->ph_var;
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phinfo->ph_eval_at = bms_del_member(phinfo->ph_eval_at, relid);
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phinfo->ph_eval_at = bms_del_member(phinfo->ph_eval_at, ojrelid);
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Assert(!bms_is_empty(phinfo->ph_eval_at));
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Assert(!bms_is_empty(phinfo->ph_eval_at)); /* checked previously */
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phinfo->ph_needed = bms_del_member(phinfo->ph_needed, relid);
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phinfo->ph_needed = bms_del_member(phinfo->ph_needed, ojrelid);
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/* ph_needed might or might not become empty */
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phv->phrels = bms_del_member(phv->phrels, relid);
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phv->phrels = bms_del_member(phv->phrels, ojrelid);
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Assert(!bms_is_empty(phv->phrels));
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Assert(phv->phnullingrels == NULL); /* no need to adjust */
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}
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}
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@ -5052,6 +5052,22 @@ from int4_tbl as t1
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One-Time Filter: false
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(5 rows)
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-- per further discussion of bug #17781
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explain (costs off)
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select ss1.x
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from (select f1/2 as x from int4_tbl i4 left join a on a.id = i4.f1) ss1
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right join int8_tbl i8 on true
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where current_user is not null; -- this is to add a Result node
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QUERY PLAN
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-----------------------------------------------
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Result
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One-Time Filter: (CURRENT_USER IS NOT NULL)
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-> Nested Loop Left Join
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-> Seq Scan on int8_tbl i8
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-> Materialize
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-> Seq Scan on int4_tbl i4
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(6 rows)
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-- check that join removal works for a left join when joining a subquery
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-- that is guaranteed to be unique by its GROUP BY clause
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explain (costs off)
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@ -1813,6 +1813,13 @@ from int4_tbl as t1
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on t5.q1 = t7.q2)
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on false;
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-- per further discussion of bug #17781
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explain (costs off)
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select ss1.x
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from (select f1/2 as x from int4_tbl i4 left join a on a.id = i4.f1) ss1
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right join int8_tbl i8 on true
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where current_user is not null; -- this is to add a Result node
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-- check that join removal works for a left join when joining a subquery
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-- that is guaranteed to be unique by its GROUP BY clause
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explain (costs off)
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