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Make the behavior of HAVING without GROUP BY conform to the SQL spec.
Formerly, if such a clause contained no aggregate functions we mistakenly treated it as equivalent to WHERE. Per spec it must cause the query to be treated as a grouped query of a single group, the same as appearance of aggregate functions would do. Also, the HAVING filter must execute after aggregate function computation even if it itself contains no aggregate functions.
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@@ -21,7 +21,7 @@ SELECT b, c FROM test_having
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3 | bbbb
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(2 rows)
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-- HAVING is equivalent to WHERE in this case
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-- HAVING is effectively equivalent to WHERE in this case
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SELECT b, c FROM test_having
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GROUP BY b, c HAVING b = 3 ORDER BY b, c;
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b | c
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@@ -49,4 +49,41 @@ SELECT c, max(a) FROM test_having
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bbbb | 5
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(2 rows)
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-- test degenerate cases involving HAVING without GROUP BY
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-- Per SQL spec, these should generate 0 or 1 row, even without aggregates
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SELECT min(a), max(a) FROM test_having HAVING min(a) = max(a);
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min | max
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-----+-----
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(0 rows)
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SELECT min(a), max(a) FROM test_having HAVING min(a) < max(a);
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min | max
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-----+-----
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0 | 9
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(1 row)
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-- errors: ungrouped column references
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SELECT a FROM test_having HAVING min(a) < max(a);
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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SELECT 1 AS one FROM test_having HAVING a > 1;
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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-- the really degenerate case: need not scan table at all
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SELECT 1 AS one FROM test_having HAVING 1 > 2;
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one
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-----
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(0 rows)
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SELECT 1 AS one FROM test_having HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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-- and just to prove that we aren't scanning the table:
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SELECT 1 AS one FROM test_having WHERE 1/a = 1 HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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DROP TABLE test_having;
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@@ -21,7 +21,7 @@ SELECT b, c FROM test_having
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3 | bbbb
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(2 rows)
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-- HAVING is equivalent to WHERE in this case
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-- HAVING is effectively equivalent to WHERE in this case
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SELECT b, c FROM test_having
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GROUP BY b, c HAVING b = 3 ORDER BY b, c;
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b | c
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@@ -49,4 +49,41 @@ SELECT c, max(a) FROM test_having
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XXXX | 0
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(2 rows)
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-- test degenerate cases involving HAVING without GROUP BY
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-- Per SQL spec, these should generate 0 or 1 row, even without aggregates
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SELECT min(a), max(a) FROM test_having HAVING min(a) = max(a);
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min | max
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-----+-----
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(0 rows)
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SELECT min(a), max(a) FROM test_having HAVING min(a) < max(a);
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min | max
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-----+-----
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0 | 9
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(1 row)
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-- errors: ungrouped column references
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SELECT a FROM test_having HAVING min(a) < max(a);
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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SELECT 1 AS one FROM test_having HAVING a > 1;
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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-- the really degenerate case: need not scan table at all
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SELECT 1 AS one FROM test_having HAVING 1 > 2;
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one
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-----
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(0 rows)
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SELECT 1 AS one FROM test_having HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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-- and just to prove that we aren't scanning the table:
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SELECT 1 AS one FROM test_having WHERE 1/a = 1 HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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DROP TABLE test_having;
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@@ -21,7 +21,7 @@ SELECT b, c FROM test_having
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3 | bbbb
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(2 rows)
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-- HAVING is equivalent to WHERE in this case
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-- HAVING is effectively equivalent to WHERE in this case
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SELECT b, c FROM test_having
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GROUP BY b, c HAVING b = 3 ORDER BY b, c;
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b | c
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@@ -49,4 +49,41 @@ SELECT c, max(a) FROM test_having
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XXXX | 0
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(2 rows)
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-- test degenerate cases involving HAVING without GROUP BY
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-- Per SQL spec, these should generate 0 or 1 row, even without aggregates
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SELECT min(a), max(a) FROM test_having HAVING min(a) = max(a);
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min | max
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-----+-----
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(0 rows)
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SELECT min(a), max(a) FROM test_having HAVING min(a) < max(a);
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min | max
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-----+-----
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0 | 9
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(1 row)
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-- errors: ungrouped column references
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SELECT a FROM test_having HAVING min(a) < max(a);
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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SELECT 1 AS one FROM test_having HAVING a > 1;
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ERROR: column "test_having.a" must appear in the GROUP BY clause or be used in an aggregate function
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-- the really degenerate case: need not scan table at all
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SELECT 1 AS one FROM test_having HAVING 1 > 2;
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one
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-----
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(0 rows)
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SELECT 1 AS one FROM test_having HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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-- and just to prove that we aren't scanning the table:
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SELECT 1 AS one FROM test_having WHERE 1/a = 1 HAVING 1 < 2;
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one
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-----
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1
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(1 row)
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DROP TABLE test_having;
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@@ -18,7 +18,7 @@ INSERT INTO test_having VALUES (9, 4, 'CCCC', 'j');
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SELECT b, c FROM test_having
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GROUP BY b, c HAVING count(*) = 1 ORDER BY b, c;
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-- HAVING is equivalent to WHERE in this case
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-- HAVING is effectively equivalent to WHERE in this case
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SELECT b, c FROM test_having
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GROUP BY b, c HAVING b = 3 ORDER BY b, c;
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@@ -30,4 +30,21 @@ SELECT c, max(a) FROM test_having
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GROUP BY c HAVING count(*) > 2 OR min(a) = max(a)
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ORDER BY c;
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-- test degenerate cases involving HAVING without GROUP BY
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-- Per SQL spec, these should generate 0 or 1 row, even without aggregates
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SELECT min(a), max(a) FROM test_having HAVING min(a) = max(a);
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SELECT min(a), max(a) FROM test_having HAVING min(a) < max(a);
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-- errors: ungrouped column references
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SELECT a FROM test_having HAVING min(a) < max(a);
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SELECT 1 AS one FROM test_having HAVING a > 1;
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-- the really degenerate case: need not scan table at all
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SELECT 1 AS one FROM test_having HAVING 1 > 2;
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SELECT 1 AS one FROM test_having HAVING 1 < 2;
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-- and just to prove that we aren't scanning the table:
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SELECT 1 AS one FROM test_having WHERE 1/a = 1 HAVING 1 < 2;
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DROP TABLE test_having;
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