mirror of
https://github.com/postgres/postgres.git
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Add in D'Arcy's cash code
pg_proc.h still needs modifying, but this gets it in there so that we can get around any compiler bugs. Will try and get the pg_proc.h entries done up later tonight...
This commit is contained in:
@@ -4,7 +4,7 @@
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# Makefile for utils/adt
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# Makefile for utils/adt
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#
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#
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# IDENTIFICATION
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# IDENTIFICATION
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# $Header: /cvsroot/pgsql/src/backend/utils/adt/Makefile,v 1.7 1997/03/14 23:19:50 scrappy Exp $
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# $Header: /cvsroot/pgsql/src/backend/utils/adt/Makefile,v 1.8 1997/04/09 08:36:04 scrappy Exp $
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#
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#
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#-------------------------------------------------------------------------
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#-------------------------------------------------------------------------
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@@ -17,7 +17,7 @@ INCLUDE_OPT = -I../.. \
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CFLAGS+=$(INCLUDE_OPT)
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CFLAGS+=$(INCLUDE_OPT)
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OBJS = acl.o arrayfuncs.o arrayutils.o bool.o char.o chunk.o date.o \
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OBJS = acl.o arrayfuncs.o arrayutils.o bool.o cash.o char.o chunk.o date.o \
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datum.o dt.o filename.o float.o geo_ops.o geo_selfuncs.o int.o \
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datum.o dt.o filename.o float.o geo_ops.o geo_selfuncs.o int.o \
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misc.o nabstime.o name.o not_in.o numutils.o oid.o \
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misc.o nabstime.o name.o not_in.o numutils.o oid.o \
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oidname.o oidint2.o oidint4.o oracle_compat.o regexp.o regproc.o \
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oidname.o oidint2.o oidint4.o oracle_compat.o regexp.o regproc.o \
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309
src/backend/utils/adt/cash.c
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309
src/backend/utils/adt/cash.c
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@@ -0,0 +1,309 @@
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/*
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cash.c
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Written by D'Arcy J.M. Cain
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Functions to allow input and output of money normally but store
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and handle it as longs
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Set tabstops to 4 for best results
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A slightly modified version of this file and a discussion of the
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workings can be found in the book "Software Solutions in C" by
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Dale Schumacher, Academic Press, ISBN: 0-12-632360-7.
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*/
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#include <stdio.h>
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#include <string.h>
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#include <limits.h>
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#include <ctype.h>
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#include <locale.h>
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#ifdef TEST_MAIN
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# include <stdlib.h>
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# define palloc malloc
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#else
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# include <palloc.h>
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#endif
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#include "cash.h"
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/* when we go to 64 bit values we will have to modify this */
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#define CASH_BUFSZ 24
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#define TERMINATOR (CASH_BUFSZ - 1)
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#define LAST_PAREN (TERMINATOR - 1)
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#define LAST_DIGIT (LAST_PAREN - 1)
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/* function to convert a long to a dollars and cents representation */
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const char *
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cash_out(long value)
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{
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char *retbuf, buf[CASH_BUFSZ];
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struct lconv *lc = localeconv();
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int mod_group = *lc->mon_grouping;
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int comma = *lc->mon_thousands_sep;
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int points = lc->frac_digits; /* int_frac_digits? */
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int minus = 0;
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int count = LAST_DIGIT;
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int point_pos;
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int comma_position = 0;
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/* frac_digits in the C locale seems to return CHAR_MAX */
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/* best guess is 2 in this case I think */
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if (points == CHAR_MAX)
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points = 2;
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point_pos = LAST_DIGIT - points;
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/* We're playing a little fast and loose with this. Shoot me. */
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if (!mod_group || mod_group == CHAR_MAX)
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mod_group = 3;
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/* allow more than three decimal points and separate them */
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if (comma)
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{
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point_pos -= (points - 1)/mod_group;
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comma_position = point_pos % (mod_group + 1);
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}
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/* we work with positive amounts and add the minus sign at the end */
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if (value < 0)
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{
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minus = 1;
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value *= -1;
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}
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/* allow for trailing negative strings */
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memset(buf, ' ', CASH_BUFSZ);
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buf[TERMINATOR] = buf[LAST_PAREN] = 0;
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while (value || count > (point_pos - 2))
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{
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if (points && count == point_pos)
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buf[count--] = *lc->decimal_point;
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else if (comma && count % (mod_group + 1) == comma_position)
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buf[count--] = comma;
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buf[count--] = (value % 10) + '0';
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value /= 10;
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}
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if (buf[LAST_DIGIT] == ',')
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buf[LAST_DIGIT] = buf[LAST_PAREN];
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/* see if we need to signify negative amount */
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if (minus)
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{
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retbuf = palloc(CASH_BUFSZ + 2 - count + strlen(lc->negative_sign));
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/* Position code of 0 means use parens */
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if (!lc->n_sign_posn)
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sprintf(retbuf, "(%s)", buf + count);
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else if (lc->n_sign_posn == 2)
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sprintf(retbuf, "%s%s", buf + count, lc->negative_sign);
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else
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sprintf(retbuf, "%s%s", lc->negative_sign, buf + count);
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}
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else
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{
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retbuf = palloc(CASH_BUFSZ + 2 - count);
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strcpy(retbuf, buf + count);
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}
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return retbuf;
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}
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/* convert a string to a long integer */
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long
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cash_in(const char *s)
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{
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long value = 0;
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long dec = 0;
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long sgn = 1;
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int seen_dot = 0;
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struct lconv *lc = localeconv();
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int fpoint = lc->frac_digits; /* int_frac_digits? */
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/* we need to add all sorts of checking here. For now just */
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/* strip all leading whitespace and any leading dollar sign */
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while (isspace(*s) || *s == '$')
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s++;
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/* a leading minus or paren signifies a negative number */
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/* again, better heuristics needed */
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if (*s == '-' || *s == '(')
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{
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sgn = -1;
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s++;
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}
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else if (*s == '+')
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s++;
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/* frac_digits in the C locale seems to return CHAR_MAX */
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/* best guess is 2 in this case I think */
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if (fpoint == CHAR_MAX)
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fpoint = 2;
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for (; ; s++)
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{
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/* we look for digits as long as we have less */
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/* than the required number of decimal places */
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if (isdigit(*s) && dec < fpoint)
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{
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value = (value * 10) + *s - '0';
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if (seen_dot)
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dec++;
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}
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else if (*s == *lc->decimal_point && !seen_dot)
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seen_dot = 1;
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else
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{
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/* round off */
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if (isdigit(*s) && *s >= '5')
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value++;
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/* adjust for less than required decimal places */
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for (; dec < fpoint; dec++)
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value *= 10;
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return(value * sgn);
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}
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}
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}
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/* used by cash_words_out() below */
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static const char *
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num_word(int value)
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{
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static char buf[128];
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static const char *small[] = {
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"zero", "one", "two", "three", "four", "five", "six", "seven",
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"eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
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"fifteen", "sixteen", "seventeen", "eighteen", "nineteen", "twenty",
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"thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety"
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};
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const char **big = small + 18;
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int tu = value % 100;
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/* deal with the simple cases first */
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if (value <= 20)
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return(small[value]);
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/* is it an even multiple of 100? */
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if (!tu)
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{
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sprintf(buf, "%s hundred", small[value/100]);
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return(buf);
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}
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/* more than 99? */
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if (value > 99)
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{
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/* is it an even multiple of 10 other than 10? */
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if (value % 10 == 0 && tu > 10)
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sprintf(buf, "%s hundred %s",
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small[value/100], big[tu/10]);
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else if (tu < 20)
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sprintf(buf, "%s hundred and %s",
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small[value/100], small[tu]);
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else
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sprintf(buf, "%s hundred %s %s",
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small[value/100], big[tu/10], small[tu % 10]);
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}
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else
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{
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/* is it an even multiple of 10 other than 10? */
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if (value % 10 == 0 && tu > 10)
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sprintf(buf, "%s", big[tu/10]);
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else if (tu < 20)
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sprintf(buf, "%s", small[tu]);
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else
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sprintf(buf, "%s %s", big[tu/10], small[tu % 10]);
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}
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return(buf);
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}
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/* this converts a long as well but to a representation using words */
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/* obviously way North American centric - sorry */
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const char *
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cash_words_out(long value)
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{
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static char buf[128];
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char *p = buf;
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long m0;
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long m1;
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long m2;
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long m3;
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/* work with positive numbers */
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if (value < 0)
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{
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value *= -1;
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strcpy(buf, "minus ");
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p += 6;
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}
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else
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*buf = 0;
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m0 = value % 100; /* cents */
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m1 = (value/100) % 1000; /* hundreds */
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m2 = (value/100000) % 1000; /* thousands */
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m3 = value/100000000 % 1000; /* millions */
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if (m3)
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{
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strcat(buf, num_word(m3));
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strcat(buf, " million ");
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}
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if (m2)
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{
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strcat(buf, num_word(m2));
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strcat(buf, " thousand ");
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}
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if (m1)
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strcat(buf, num_word(m1));
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if (!*p)
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strcat(buf, "zero");
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strcat(buf, (int)(value/100) == 1 ? " dollar and " : " dollars and ");
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strcat(buf, num_word(m0));
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strcat(buf, m0 == 1 ? " cent" : " cents");
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*buf = toupper(*buf);
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return(buf);
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}
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#include <stdlib.h>
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#ifdef TEST_MAIN
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int
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main(void)
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{
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char p[64], *q;
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long v; /* the long value representing the amount */
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int d; /* number of decimal places - default 2 */
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while (fgets(p, sizeof(p), stdin) != NULL)
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{
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if ((q = strchr(p, '\n')) != NULL)
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*q = 0;
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for (q = p; *q && !isspace(*q); q++)
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;
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v = cash_in(p);
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d = *q ? atoi(q) : 2;
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printf("%12.12s %10ld ", p, v);
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printf("%12s %s\n", cash_out(v), cash_words_out(v));
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}
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return(0);
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}
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#endif /* TEST_MAIN */
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16
src/include/utils/cash.h
Normal file
16
src/include/utils/cash.h
Normal file
@@ -0,0 +1,16 @@
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/*
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cash.h
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Written by D'Arcy J.M. Cain
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functions to allow input and output of money normally but store
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and handle it as long integers
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*/
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#ifndef _CASH_H
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#define _CASH_H
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const char *cash_out(long value);
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long cash_in(const char *str);
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const char *cash_words_out(long value);
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#endif /* _CASH_H */
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Reference in New Issue
Block a user