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If a range-partitioned table has no default partition, reject null keys.
Commit 4e5fe9ad19 introduced this
problem. Also add a test so it doesn't get broken again.
Report by Rushabh Lathia. Fix by Amit Langote. Reviewed by Rushabh
Lathia and Amul Sul. Tweaked by me.
Discussion: http://postgr.es/m/CAGPqQf0Y1iJyk4QJBdMf=pS9i6Q0JUMM_h5-qkR3OMJ-e04PyA@mail.gmail.com
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@@ -2553,11 +2553,10 @@ get_partition_for_tuple(Relation relation, Datum *values, bool *isnull)
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*/
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for (i = 0; i < key->partnatts; i++)
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{
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if (isnull[i] &&
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partition_bound_has_default(partdesc->boundinfo))
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if (isnull[i])
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{
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range_partkey_has_null = true;
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part_index = partdesc->boundinfo->default_index;
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break;
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}
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}
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