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mariadb/mysql-test
Jorgen Loland 92eab9957d BUG#12561818 - RERUN OF STORED FUNCTION GIVES ERROR 1172:
RESULT CONSISTED OF MORE THAN ONE ROW

MySQL converts incorrect DATEs and DATETIMEs to '0000-00-00' on
insertion by default. This means that this sequence is possible:

CREATE TABLE t1(date_notnull DATE NOT NULL);
INSERT INTO t1 values (NULL);
SELECT * FROM t1;
0000-00-00

At the same time, ODBC drivers do not (or at least did not in the
90's) understand the DATE and DATETIME value '0000-00-00'. Thus,
to be able to query for the value 0000-00-00 it was decided in
MySQL 4.x (or maybe even before that) that for the special case
of DATE/DATETIME NOT NULL columns, the query "SELECT ... WHERE
date_notnull IS NULL" should return rows with date_notnull ==
'0000-00-00'. This is documented misbehavior that we do not want
to change.

The hack used to make MySQL return these rows is to convert 
"date_notnull IS NULL" to "date_notnull = 0". This is, however,
only done if the table date_notnull belongs to is not an inner
table of an outer join. The rationale for this seems to be that
if there is no join match for the row in the outer table,
null-complemented rows would otherwise not be returned because
the null-complemented DATE value is actually NULL. On the other
hand, this means that the "return rows with 0000-00-00 when the
query asks for IS NULL"-hack is not in effect for outer joins.

In this bug, we have a LEFT JOIN that does not misbehave like 
the documentation says it should. The fix is to rewrite

"date_notnull IS NULL" to "date_notnull IS NULL OR 
                           date_notnull = 0"
if dealing with an OUTER JOIN, otherwise 
"date_notnull IS NULL" to "date_notnull = 0"
as was done before.

Note:
The bug was originally reported as different result on first 
and second execution of SP. The reason was that during first
execution the query was correctly rewritten to an inner join
due to a null-rejecting predicate. On second execution the
"IS NULL" -> "= 0" rewrite was done because there was no outer
join. The real problem, though, was incorrect date/datetime 
IS NULL handling for OUTER JOINs.

mysql-test/r/type_datetime.result:
  Add test for BUG#12561818
mysql-test/t/type_datetime.test:
  Add test for BUG#12561818
sql/sql_select.cc:
  Special handling of NULL for DATE/DATETIME NOT NULL columns:
  In the case of outer join,
  "date_notnull IS NULL" 
  is now rewritten to
  "date_notnull IS NULL OR date_notnull = 0"
2011-06-10 10:22:45 +02:00
..
2011-06-06 13:24:28 +03:00
2011-03-25 15:03:44 +01:00
2010-12-28 19:57:23 +01:00

This directory contains a test suite for the MySQL daemon. To run
the currently existing test cases, simply execute ./mysql-test-run in
this directory. It will fire up the newly built mysqld and test it.

Note that you do not have to have to do "make install", and you could
actually have a co-existing MySQL installation. The tests will not
conflict with it.

All tests must pass. If one or more of them fail on your system, please
read the following manual section for instructions on how to report the
problem:

http://dev.mysql.com/doc/mysql/en/mysql-test-suite.html

If you want to use an already running MySQL server for specific tests,
use the --extern option to mysql-test-run. Please note that in this mode,
the test suite expects you to provide the names of the tests to run.
For example, here is the command to run the "alias" and "analyze" tests
with an external server:

mysql-test-run --extern alias analyze

To match your setup, you might also need to provide --socket, --user, and
other relevant options.

With no test cases named on the command line, mysql-test-run falls back
to the normal "non-extern" behavior. The reason for this is that some
tests cannot run with an external server.


You can create your own test cases. To create a test case, create a new
file in the t subdirectory using a text editor. The file should have a .test
extension. For example:

 xemacs t/test_case_name.test

 In the file, put a set of SQL statements that create some tables,
 load test data, and run some queries to manipulate it.

 We would appreciate it if you name your test tables t1, t2, t3 ... (to not
 conflict too much with existing tables).

 Your test should begin by dropping the tables you are going to create and
 end by dropping them again.  This ensures that you can run the test over
 and over again.
 
 If you are using mysqltest commands (like result file names) in your
 test case, you should create the result file as follows:

 mysql-test-run --record test_case_name

 or

 mysqltest --record < t/test_case_name.test

 If you only have a simple test cases consisting of SQL statements and
 comments, you can create the test case in one of the following ways:

 mysql-test-run --record test_case_name

 mysql test < t/test_case_name.test > r/test_case_name.result

 mysqltest --record --record-file=r/test_case_name.result < t/test_case_name.test

 When this is done, take a look at r/test_case_name.result
 - If the result is incorrect, you have found a bug. In this case, you should
   edit the test result to the correct results so that we can verify
   that the bug is corrected in future releases.

To submit your test case, put your .test file and .result file(s) into
a tar.gz archive, add a README that explains the problem, ftp the 
archive to ftp://support.mysql.com/pub/mysql/secret/ and send a mail
to bugs@lists.mysql.com