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a46d7542c9
The main idea is to exploit the fact that key scans for "key=const" return ordered sequences of rowids.
79 lines
2.7 KiB
C
79 lines
2.7 KiB
C
/* Copyright (C) 2000 MySQL AB
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 2 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program; if not, write to the Free Software
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Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA */
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/* Some useful bit functions */
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#include "mysys_priv.h"
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/*
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Find smallest X in 2^X >= value
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This can be used to divide a number with value by doing a shift instead
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*/
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uint my_bit_log2(ulong value)
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{
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uint bit;
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for (bit=0 ; value > 1 ; value>>=1, bit++) ;
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return bit;
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}
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static char nbits[256] = {
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0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4,
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1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
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1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
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1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
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2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
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3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
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3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7,
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4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8,
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};
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uint my_count_bits(ulonglong v)
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{
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#if SIZEOF_LONG_LONG > 4
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/* The following code is a bit faster on 16 bit machines than if we would
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only shift v */
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ulong v2=(ulong) (v >> 32);
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return (uint) (uchar) (nbits[(uchar) v] +
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nbits[(uchar) (v >> 8)] +
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nbits[(uchar) (v >> 16)] +
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nbits[(uchar) (v >> 24)] +
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nbits[(uchar) (v2)] +
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nbits[(uchar) (v2 >> 8)] +
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nbits[(uchar) (v2 >> 16)] +
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nbits[(uchar) (v2 >> 24)]);
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#else
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return (uint) (uchar) (nbits[(uchar) v] +
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nbits[(uchar) (v >> 8)] +
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nbits[(uchar) (v >> 16)] +
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nbits[(uchar) (v >> 24)]);
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#endif
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}
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uint my_count_bits_ushort(ushort v)
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{
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return nbits[v];
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}
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