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Fix for bug #1271: Undefined variable in PASSWORD() function is not

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handled correctly
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gluh@gluh.mysql.r18.ru
2003-10-21 15:14:06 +05:00
parent 91f5c5e337
commit f602be8d3f
3 changed files with 20 additions and 1 deletions
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10
mysql-test/r/func_crypt.result
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@@ -7,3 +7,13 @@ old_password('test') password('test')
select length(encrypt('test')), encrypt('test','aa');
length(encrypt('test')) encrypt('test','aa')
13 aaqPiZY5xR5l.
drop table if exists t1;
create table t1 (name varchar(50), pw varchar(16));
insert into t1 values ('tom', password('my_pass'));
set @pass='my_pass';
select name from t1 where name='tom' and pw=password(@pass);
name
tom
select name from t1 where name='tom' and pw=password(@undefined);
name
drop table t1;