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Bug#22312 Syntax error in expression with INTERVAL()

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Parser rejects valid INTERVAL() expressions when associated with
arithmetic operators. The problem is the way in which the expression
and interval grammar rules were organized caused shift/reduce conflicts.

The solution is to tweak the interval rules to avoid shift/reduce
conflicts by removing the broken interval_expr rule and explicitly
specify it's content where necessary.

Original fix by Davi Arnaut, revised and improved rules by Marc Alff
This commit is contained in:
davi@mysql.com/endora.local
2007-11-30 09:34:25 -02:00
parent d179bb64c2
commit ee9bafc1c5
3 changed files with 101 additions and 27 deletions
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43
mysql-test/r/parser.result
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@@ -484,3 +484,46 @@ select atan(10, 20 "p2");
ERROR 42000: Incorrect parameters in the call to native function 'atan'
select atan(10 AS p1, 20 AS p2);
ERROR 42000: Incorrect parameters in the call to native function 'atan'
DROP TABLE IF EXISTS t1;
SELECT STR_TO_DATE('10:00 PM', '%h:%i %p') + INTERVAL 10 MINUTE;
STR_TO_DATE('10:00 PM', '%h:%i %p') + INTERVAL 10 MINUTE
NULL
SELECT STR_TO_DATE('10:00 PM', '%h:%i %p') + INTERVAL (INTERVAL(1,2,3) + 1) MINUTE;
STR_TO_DATE('10:00 PM', '%h:%i %p') + INTERVAL (INTERVAL(1,2,3) + 1) MINUTE
NULL
SELECT "1997-12-31 23:59:59" + INTERVAL 1 SECOND;
"1997-12-31 23:59:59" + INTERVAL 1 SECOND
1998-01-01 00:00:00
SELECT 1 + INTERVAL(1,0,1,2) + 1;
1 + INTERVAL(1,0,1,2) + 1
4
SELECT INTERVAL(1^1,0,1,2) + 1;
INTERVAL(1^1,0,1,2) + 1
2
SELECT INTERVAL(1,0+1,2,3) * 5.5;
INTERVAL(1,0+1,2,3) * 5.5
5.5
SELECT INTERVAL(3,3,1+3,4+4) / 0.5;
INTERVAL(3,3,1+3,4+4) / 0.5
2.0000
SELECT (INTERVAL(1,0,1,2) + 5) * 7 + INTERVAL(1,0,1,2) / 2;
(INTERVAL(1,0,1,2) + 5) * 7 + INTERVAL(1,0,1,2) / 2
50.0000
SELECT INTERVAL(1,0,1,2) + 1, 5 * INTERVAL(1,0,1,2);
INTERVAL(1,0,1,2) + 1 5 * INTERVAL(1,0,1,2)
3 10
SELECT INTERVAL(0,(1*5)/2) + INTERVAL(5,4,3);
INTERVAL(0,(1*5)/2) + INTERVAL(5,4,3)
2
SELECT 1^1 + INTERVAL 1+1 SECOND & 1 + INTERVAL 1+1 SECOND;
1^1 + INTERVAL 1+1 SECOND & 1 + INTERVAL 1+1 SECOND
NULL
SELECT 1%2 - INTERVAL 1^1 SECOND | 1%2 - INTERVAL 1^1 SECOND;
1%2 - INTERVAL 1^1 SECOND | 1%2 - INTERVAL 1^1 SECOND
NULL
CREATE TABLE t1 (a INT, b DATETIME);
INSERT INTO t1 VALUES (INTERVAL(3,2,1) + 1, "1997-12-31 23:59:59" + INTERVAL 1 SECOND);
SELECT * FROM t1 WHERE a = INTERVAL(3,2,1) + 1;
a b
3 1998-01-01 00:00:00
DROP TABLE t1;