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Reverting patch for BUG #14009 (use of abs() on null value causes problems with filesort

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Fix for bug #14536: SELECT @a,@a:=... fails with prepared statements
This commit is contained in:
monty@mysql.com
2005-11-01 15:54:30 +02:00
parent f3502cd983
commit e5f48e13bf
14 changed files with 70 additions and 53 deletions
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4
mysql-test/r/func_sapdb.result
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@@ -180,8 +180,8 @@ Field Type Null Key Default Extra
f1 date NO 0000-00-00
f2 datetime YES NULL
f3 time YES NULL
f4 time NO 00:00:00
f5 time NO 00:00:00
f4 time YES NULL
f5 time YES NULL
f6 time NO 00:00:00
f7 datetime YES NULL
f8 date YES NULL

2
mysql-test/r/type_newdecimal.result
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@@ -176,7 +176,7 @@ Table Create Table
t1 CREATE TABLE `t1` (
`round(15.4,-1)` decimal(3,0) unsigned NOT NULL default '0',
`truncate(-5678.123451,-3)` decimal(4,0) NOT NULL default '0',
`abs(-1.1)` decimal(2,1) default NULL,
`abs(-1.1)` decimal(2,1) NOT NULL default '0.0',
`-(-1.1)` decimal(2,1) NOT NULL default '0.0'
) ENGINE=MyISAM DEFAULT CHARSET=latin1
drop table t1;

11
mysql-test/r/user_var.result
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@@ -123,6 +123,17 @@ select @a+0, @a:=@a+0+count(*), count(*), @a+0 from t1 group by i;
0 1 1 0
1 3 2 0
3 6 3 0
set @a=0;
select @a,@a:="hello",@a,@a:=3,@a,@a:="hello again" from t1 group by i;
@a @a:="hello" @a @a:=3 @a @a:="hello again"
0 hello 0 3 0 hello again
0 hello 0 3 0 hello again
0 hello 0 3 0 hello again
select @a,@a:="hello",@a,@a:=3,@a,@a:="hello again" from t1 group by i;
@a @a:="hello" @a @a:=3 @a @a:="hello again"
hello again hello hello again 3 hello again hello again
hello again hello hello again 3 hello again hello again
hello again hello hello again 3 hello again hello again
drop table t1;
set @a=_latin2'test';
select charset(@a),collation(@a),coercibility(@a);

1
mysql-test/t/disabled.def
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@@ -16,4 +16,3 @@ rpl_until : Unstable test case, bug#12429
rpl_deadlock : Unstable test case, bug#12429
kill : Unstable test case, bug#9712
archive_gis : The test fails on 32bit Linux
user_var : Ramil should fix this soon

4
mysql-test/t/user_var.test
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@@ -70,6 +70,10 @@ create table t1 (i int not null);
insert t1 values (1),(2),(2),(3),(3),(3);
select @a:=0; select @a, @a:=@a+count(*), count(*), @a from t1 group by i;
select @a:=0; select @a+0, @a:=@a+0+count(*), count(*), @a+0 from t1 group by i;
set @a=0;
select @a,@a:="hello",@a,@a:=3,@a,@a:="hello again" from t1 group by i;
select @a,@a:="hello",@a,@a:=3,@a,@a:="hello again" from t1 group by i;
drop table t1;
#