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Code Activity

Fixed bug in HAVING when refering to RAND() through alias

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(BUG 8216)


mysql-test/r/group_by.result:
  New test case
mysql-test/r/user_var.result:
  Test changed (to be more correct) with bug fix
mysql-test/t/group_by.test:
  Added test for HAVING bug
sql/item_cmpfunc.cc:
  Fixed bug in HAVING when refering to RAND()
sql/item_func.cc:
  Fixed bug in HAVING when refering to RAND()
sql/item_row.cc:
  Fixed bug in HAVING when refering to RAND()
sql/item_strfunc.cc:
  Fixed bug in HAVING when refering to RAND()
sql/unireg.h:
  Added PSEUDO_TABLES_BITS for easy testing of real table reference
This commit is contained in:
unknown
2005-02-07 18:13:57 +02:00
parent ad21db5e07
commit d6ed8cd709
8 changed files with 126 additions and 29 deletions
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45
mysql-test/r/group_by.result
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@ -629,15 +629,6 @@ explain SELECT i, COUNT(DISTINCT(i)) FROM t1 GROUP BY j ORDER BY NULL;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 6 Using filesort
DROP TABLE t1;
create table t1 ( col1 int, col2 int );
insert into t1 values (1,1),(1,2),(1,3),(2,1),(2,2);
select group_concat( distinct col1 ) as alias from t1
group by col2 having alias like '%';
alias
1,2
1,2
1
drop table t1;
create table t1 (a int);
insert into t1 values(null);
select min(a) is null from t1;
@ -650,3 +641,39 @@ select 1 and min(a) is null from t1;
1 and min(a) is null
1
drop table t1;
create table t1 ( col1 int, col2 int );
insert into t1 values (1,1),(1,2),(1,3),(2,1),(2,2);
select group_concat( distinct col1 ) as alias from t1
group by col2 having alias like '%';
alias
1,2
1,2
1
drop table t1;
create table t1 (a integer, b integer, c integer);
insert into t1 (a,b) values (1,2),(1,3),(2,5);
select a, 0.1*0+1 r2, sum(1) r1 from t1 where a = 1 group by a having r1>1 and r2=1;
a r2 r1
1 1.0 2
select a, rand()*0+1 r2, sum(1) r1 from t1 where a = 1 group by a having r1>1 and r2=1;
a r2 r1
1 1 2
select a,sum(b) from t1 where a=1 group by c;
a sum(b)
1 5
select a*sum(b) from t1 where a=1 group by c;
a*sum(b)
5
select sum(a)*sum(b) from t1 where a=1 group by c;
sum(a)*sum(b)
10
select a,sum(b) from t1 where a=1 group by c having a=1;
a sum(b)
1 5
select a as d,sum(b) from t1 where a=1 group by c having d=1;
d sum(b)
1 5
select sum(a)*sum(b) as d from t1 where a=1 group by c having d > 0;
d
10
drop table t1;