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MDEV-27151: JSON_VALUE() does not parse NULL properties properly

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Analysis: JSON_VALUE() returns "null" string instead of NULL pointer.
Fix: When the type is JSON_VALUE_NULL (which is also a scalar) set
null_value to true and return 0 instead of returning string.
This commit is contained in:
Rucha Deodhar
2022-08-01 19:39:09 +05:30
parent d7ba72ea9b
commit d48428e99a
3 changed files with 52 additions and 1 deletions
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19
mysql-test/main/func_json.test
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@ -627,6 +627,25 @@ SELECT * FROM t1 WHERE JSON_EXTRACT(j, '$.Age')=19;
drop table t1;
--echo #
--echo # MDEV-27151: JSON_VALUE() does not parse NULL properties properly
--echo #
--echo #
--echo # It is correct for JSON_EXTRACT() to give null instead of "NULL" because
--echo # it returns the json literal that is put inside json.
--echo # Hence it should return null as in 'null' string and not SQL NULL.
--echo # JSON_VALUE() returns the "VALUE" so it is correct for it to return SQl NULL
--echo #
SELECT NULL;
SELECT JSON_VALUE('{"nulltest": null}', '$.nulltest');
SELECT 1 + NULL;
SELECT 1 + JSON_VALUE('{"nulltest": null}', '$.nulltest');
SELECT NULL;
SELECT JSON_EXTRACT('{"a":null, "b":10, "c":"null"}', '$.a');
--echo #
--echo # End of 10.3 tests
--echo #