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Fixed bug #12762:

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allowed set functions aggregated in outer subqueries, allowed nested set functions.
This commit is contained in:
igor@rurik.mysql.com
2005-10-15 14:32:37 -07:00
parent a5c5b2c658
commit c136e9c43b
25 changed files with 772 additions and 75 deletions
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143
mysql-test/r/subselect.result
View File

@@ -2988,3 +2988,146 @@ max(fld)
1
drop table t1;
purge master logs before (select adddate(current_timestamp(), interval -4 day));
CREATE TABLE t1 (a int, b int);
CREATE TABLE t2 (c int, d int);
CREATE TABLE t3 (e int);
INSERT INTO t1 VALUES
(1,10), (2,10), (1,20), (2,20), (3,20), (2,30), (4,40);
INSERT INTO t2 VALUES
(2,10), (2,20), (4,10), (5,10), (3,20), (2,40);
INSERT INTO t3 VALUES (10), (30), (10), (20) ;
SELECT a, MAX(b), MIN(b) FROM t1 GROUP BY a;
a MAX(b) MIN(b)
1 20 10
2 30 10
3 20 20
4 40 40
SELECT * FROM t2;
c d
2 10
2 20
4 10
5 10
3 20
2 40
SELECT * FROM t3;
e
10
30
10
20
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2 WHERE MAX(b)>20);
a
2
4
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2 WHERE MAX(b)<d);
a
2
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2 WHERE MAX(b)>d);
a
2
4
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2
WHERE d >= SOME(SELECT e FROM t3 WHERE MAX(b)=e));
a
2
3
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2
WHERE EXISTS(SELECT e FROM t3 WHERE MAX(b)=e AND e <= d));
a
2
3
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2
WHERE d > SOME(SELECT e FROM t3 WHERE MAX(b)=e));
a
2
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2
WHERE EXISTS(SELECT e FROM t3 WHERE MAX(b)=e AND e < d));
a
2
SELECT a FROM t1 GROUP BY a
HAVING a IN (SELECT c FROM t2
WHERE MIN(b) < d AND
EXISTS(SELECT e FROM t3 WHERE MAX(b)=e AND e <= d));
a
2
SELECT a, SUM(a) FROM t1 GROUP BY a;
a SUM(a)
1 2
2 6
3 3
4 4
SELECT a FROM t1
WHERE EXISTS(SELECT c FROM t2 GROUP BY c HAVING SUM(a) = c) GROUP BY a;
a
3
4
SELECT a FROM t1 GROUP BY a
HAVING EXISTS(SELECT c FROM t2 GROUP BY c HAVING SUM(a) = c);
a
1
3
4
SELECT a FROM t1
WHERE a < 3 AND
EXISTS(SELECT c FROM t2 GROUP BY c HAVING SUM(a) != c) GROUP BY a;
a
1
2
SELECT a FROM t1
WHERE a < 3 AND
EXISTS(SELECT c FROM t2 GROUP BY c HAVING SUM(a) != c);
a
1
2
1
2
2
SELECT t1.a FROM t1 GROUP BY t1.a
HAVING t1.a < ALL(SELECT t2.c FROM t2 GROUP BY t2.c
HAVING EXISTS(SELECT t3.e FROM t3 GROUP BY t3.e
HAVING SUM(t1.a+t2.c) < t3.e/4));
a
1
2
SELECT t1.a FROM t1 GROUP BY t1.a
HAVING t1.a > ALL(SELECT t2.c FROM t2
WHERE EXISTS(SELECT t3.e FROM t3 GROUP BY t3.e
HAVING SUM(t1.a+t2.c) < t3.e/4));
a
4
SELECT t1.a FROM t1 GROUP BY t1.a
HAVING t1.a > ALL(SELECT t2.c FROM t2
WHERE EXISTS(SELECT t3.e FROM t3
WHERE SUM(t1.a+t2.c) < t3.e/4));
ERROR HY000: Invalid use of group function
SELECT t1.a from t1 GROUP BY t1.a HAVING AVG(SUM(t1.b)) > 20;
ERROR HY000: Invalid use of group function
SELECT t1.a FROM t1 GROUP BY t1.a
HAVING t1.a IN (SELECT t2.c FROM t2 GROUP BY t2.c
HAVING AVG(t2.c+SUM(t1.b)) > 20);
a
2
3
4
SELECT t1.a FROM t1 GROUP BY t1.a
HAVING t1.a IN (SELECT t2.c FROM t2 GROUP BY t2.c
HAVING AVG(SUM(t1.b)) > 20);
a
2
4
SELECT t1.a, SUM(b) AS sum FROM t1 GROUP BY t1.a
HAVING t1.a IN (SELECT t2.c FROM t2 GROUP BY t2.c
HAVING t2.c+sum > 20);
a sum
2 60
3 20
4 40
DROP TABLE t1,t2,t3;