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Bug #14637: trim trailing spaces processes data only byte wise
(From: gkodinov) Use and int * where possible to scan for trailing space in a string instead of always iterating char-by-char. Using the attached benchmark file on a 32 bit Intel Core 2 Duo CPU I've got 43485 ms run with the fix compared to 44373 without it. Backported to 5.6.0 (next-mr-runtime) 6.0-codebase revid: 2476.1362.1
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@ -266,4 +266,74 @@ typedef struct st_mysql_lex_string LEX_STRING;
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#define USTRING_WITH_LEN(X) ((uchar*) X), ((size_t) (sizeof(X) - 1))
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#define C_STRING_WITH_LEN(X) ((char *) (X)), ((size_t) (sizeof(X) - 1))
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/* SPACE_INT is a word that contains only spaces */
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#if SIZEOF_INT == 4
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#define SPACE_INT 0x20202020
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#elif SIZEOF_INT == 8
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#define SPACE_INT 0x2020202020202020
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#else
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#error define the appropriate constant for a word full of spaces
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#endif
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/**
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Skip trailing space.
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On most systems reading memory in larger chunks (ideally equal to the size of
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the chinks that the machine physically reads from memory) causes fewer memory
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access loops and hence increased performance.
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This is why the 'int' type is used : it's closest to that (according to how
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it's defined in C).
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So when we determine the amount of whitespace at the end of a string we do
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the following :
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1. We divide the string into 3 zones :
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a) from the start of the string (__start) to the first multiple
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of sizeof(int) (__start_words)
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b) from the end of the string (__end) to the last multiple of sizeof(int)
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(__end_words)
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c) a zone that is aligned to sizeof(int) and can be safely accessed
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through an int *
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2. We start comparing backwards from (c) char-by-char. If all we find is
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space then we continue
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3. If there are elements in zone (b) we compare them as unsigned ints to a
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int mask (SPACE_INT) consisting of all spaces
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4. Finally we compare the remaining part (a) of the string char by char.
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This covers for the last non-space unsigned int from 3. (if any)
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This algorithm works well for relatively larger strings, but it will slow
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the things down for smaller strings (because of the additional calculations
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and checks compared to the naive method). Thus the barrier of length 20
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is added.
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@param ptr pointer to the input string
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@param len the length of the string
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@return the last non-space character
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*/
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static inline const uchar *skip_trailing_space(const uchar *ptr,size_t len)
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{
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const uchar *start= ptr;
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const uchar *end= ptr + len;
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if (len > 20)
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{
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const uchar *end_words= (const uchar *)
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(((intptr)end) / SIZEOF_INT * SIZEOF_INT);
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const uchar *start_words= (const uchar *)
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((((intptr)start) + SIZEOF_INT - 1) / SIZEOF_INT * SIZEOF_INT);
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DBUG_ASSERT(((intptr)start) >= SIZEOF_INT);
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if (end_words > start)
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{
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while (end > end_words && end[-1] == 0x20)
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end--;
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if (end[-1] == 0x20 && start_words < end_words)
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while (end > start_words && ((unsigned *)end)[-1] == SPACE_INT)
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end -= SIZEOF_INT;
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}
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}
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while (end > start && end[-1] == 0x20)
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end--;
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return (end);
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}
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#endif
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@ -278,14 +278,11 @@ void my_hash_sort_8bit_bin(CHARSET_INFO *cs __attribute__((unused)),
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{
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const uchar *pos = key;
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key+= len;
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/*
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Remove trailing spaces. We have to do this to be able to compare
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'A ' and 'A' as identical
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*/
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while (key > pos && key[-1] == ' ')
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key--;
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key= skip_trailing_space(key, len);
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for (; pos < (uchar*) key ; pos++)
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{
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@ -678,13 +678,12 @@ void my_hash_sort_latin1_de(CHARSET_INFO *cs __attribute__((unused)),
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const uchar *key, size_t len,
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ulong *nr1, ulong *nr2)
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{
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const uchar *end= key+len;
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const uchar *end;
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/*
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Remove end space. We have to do this to be able to compare
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'AE' and '<27>' as identical
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*/
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while (end > key && end[-1] == ' ')
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end--;
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end= skip_trailing_space(key, len);
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for (; key < end ; key++)
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{
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@ -469,14 +469,11 @@ static void my_hash_sort_mb_bin(CHARSET_INFO *cs __attribute__((unused)),
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{
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const uchar *pos = key;
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key+= len;
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/*
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Remove trailing spaces. We have to do this to be able to compare
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'A ' and 'A' as identical
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*/
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while (key > pos && key[-1] == ' ')
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key--;
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key= skip_trailing_space(key, len);
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for (; pos < (uchar*) key ; pos++)
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{
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@ -304,14 +304,13 @@ void my_hash_sort_simple(CHARSET_INFO *cs,
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ulong *nr1, ulong *nr2)
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{
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register uchar *sort_order=cs->sort_order;
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const uchar *end= key + len;
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const uchar *end;
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/*
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Remove end space. We have to do this to be able to compare
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'A ' and 'A' as identical
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*/
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while (end > key && end[-1] == ' ')
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end--;
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end= skip_trailing_space(key, len);
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for (; key < (uchar*) end ; key++)
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{
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@ -1165,9 +1164,8 @@ size_t my_well_formed_len_8bit(CHARSET_INFO *cs __attribute__((unused)),
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size_t my_lengthsp_8bit(CHARSET_INFO *cs __attribute__((unused)),
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const char *ptr, size_t length)
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{
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const char *end= ptr+length;
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while (end > ptr && end[-1] == ' ')
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end--;
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const char *end;
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end= (const char *) skip_trailing_space((const uchar *)ptr, length);
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return (size_t) (end-ptr);
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}
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