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Bug#15728: LAST_INSERT_ID function inside a stored function returns 0

Do not reset value of LAST_INSERT_ID() in sub-statement.
This commit is contained in:
kroki@mysql.com
2006-04-21 18:55:04 +04:00
parent 8532fa29f4
commit b0c1e49a11
5 changed files with 173 additions and 2 deletions

View File

@ -74,3 +74,61 @@ SET FOREIGN_KEY_CHECKS=0;
INSERT INTO t1 VALUES (1),(1);
ERROR 23000: Duplicate entry '1' for key 1
drop table t1;
drop function if exists bug15728;
drop function if exists bug15728_insert;
drop table if exists t1, t2;
create table t1 (
id int not null auto_increment,
last_id int,
primary key (id)
);
create function bug15728() returns int(11)
return last_insert_id();
insert into t1 (last_id) values (0);
insert into t1 (last_id) values (last_insert_id());
insert into t1 (last_id) values (bug15728());
create table t2 (
id int not null auto_increment,
last_id int,
primary key (id)
);
create function bug15728_insert() returns int(11) modifies sql data
begin
insert into t2 (last_id) values (bug15728());
return bug15728();
end|
create trigger t1_bi before insert on t1 for each row
begin
declare res int;
select bug15728_insert() into res;
set NEW.last_id = res;
end|
insert into t1 (last_id) values (0);
drop trigger t1_bi;
select last_insert_id();
last_insert_id()
4
select bug15728_insert();
bug15728_insert()
2
select last_insert_id();
last_insert_id()
4
insert into t1 (last_id) values (bug15728());
select last_insert_id();
last_insert_id()
5
select * from t1;
id last_id
1 0
2 1
3 2
4 1
5 4
select * from t2;
id last_id
1 3
2 4
drop function bug15728;
drop function bug15728_insert;
drop table t1, t2;