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Fixed the bug mdev-12429 and its duplicates mdev-12145 and mdev-9886.

Browse Source 
Also fixed a wrong result for a test case for mdev-7691
(the alternative one).
The test  cases for all these bug have materialized semi-joins used
inside dependent sub-queries.

The patch actually reverts the change inroduced by Monty in 2003.
It looks like this change is not valid anymore after the implementation
of semi-joins.
Adjusted output from EXPLAIN for many other test cases.
This commit is contained in:
Igor Babaev
2017-04-04 10:04:52 -07:00
parent a821ef7605
commit b0395d8701
15 changed files with 329 additions and 22 deletions
Download Patch File Download Diff File Expand all files Collapse all files

8
mysql-test/r/subselect4.result
View File

@ -19,7 +19,7 @@ SELECT 1 FROM t1
WHERE NOT EXISTS (SELECT 1 FROM t2 WHERE 1 = (SELECT MIN(t2.b) FROM t3))
ORDER BY count(*);
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY t1 index NULL a 5 NULL 2 Using where; Using index; Using temporary
1 PRIMARY t1 index NULL a 5 NULL 2 Using index; Using temporary
2 DEPENDENT SUBQUERY t2 ALL NULL NULL NULL NULL 2 Using where
3 DEPENDENT SUBQUERY t3 system NULL NULL NULL NULL 0 const row not found
# should not crash the next statement
@ -1418,7 +1418,7 @@ GROUP BY f9;
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY NULL NULL NULL NULL NULL NULL NULL Impossible WHERE
3 SUBQUERY NULL NULL NULL NULL NULL NULL NULL Impossible WHERE noticed after reading const tables
2 DEPENDENT SUBQUERY t1 ALL NULL NULL NULL NULL 2 Using where
2 DEPENDENT SUBQUERY t1 ALL NULL NULL NULL NULL 2
SELECT COUNT(t2.f3),
(SELECT COUNT(f3) FROM t1 WHERE t2.f1) AS f9
FROM t2 JOIN t1 ON t1.f3
@ -1434,7 +1434,7 @@ ORDER BY f9;
id select_type table type possible_keys key key_len ref rows Extra
1 PRIMARY NULL NULL NULL NULL NULL NULL NULL Impossible WHERE
3 SUBQUERY NULL NULL NULL NULL NULL NULL NULL Impossible WHERE noticed after reading const tables
2 DEPENDENT SUBQUERY t1 ALL NULL NULL NULL NULL 2 Using where
2 DEPENDENT SUBQUERY t1 ALL NULL NULL NULL NULL 2
SELECT COUNT(t2.f3),
(SELECT COUNT(f3) FROM t1 WHERE t2.f1) AS f9
FROM t2 JOIN t1 ON t1.f3
@ -2444,9 +2444,11 @@ WHERE EXISTS (
)";
EXECUTE stmt;
i
4
6
EXECUTE stmt;
i
4
6
drop table t1, t2, t3;
#