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Merge olga.mysql.com:/home/igor/mysql-5.0-opt

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into  olga.mysql.com:/home/igor/dev-opt/mysql-5.0-opt-bug24345
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igor@olga.mysql.com
2007-01-09 00:17:48 -08:00
parent a63df24a68 08369f4bce
commit ae6bee30fc
3 changed files with 105 additions and 1 deletions
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12
sql/sql_select.cc
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@ -2305,8 +2305,18 @@ make_join_statistics(JOIN *join, TABLE_LIST *tables, COND *conds,
substitution of a const table the key value happens to be null
then we can state that there are no matches for this equi-join.
*/
if ((keyuse= s->keyuse) && *s->on_expr_ref)
if ((keyuse= s->keyuse) && *s->on_expr_ref && !s->embedding_map)
{
/*
When performing an outer join operation if there are no matching rows
for the single row of the outer table all the inner tables are to be
null complemented and thus considered as constant tables.
Here we apply this consideration to the case of outer join operations
with a single inner table only because the case with nested tables
would require a more thorough analysis.
TODO. Apply single row substitution to null complemented inner tables
for nested outer join operations.
*/
while (keyuse->table == table)
{
if (!(keyuse->val->used_tables() & ~join->const_table_map) &&