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Bug#11756928 48916: SERVER INCORRECTLY PROCESSING HAVING CLAUSES WITH AN ORDER BY CLAUSE

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Before sorting HAVING condition is split into two parts,
first part is a table related condition and the rest of is
HAVING part. Extraction of HAVING part does not take into account
the fact that some of conditions might be non-const but
have 'used_tables' == 0 (independent subqueries)
and because of that these conditions are cut off by
make_cond_for_table() function.
The fix is to use (table_map) 0 instead of used_tables in
third argument for make_cond_for_table() function.
It allows to extract elements which belong to sorted
table and in addition elements which are independend
subqueries.


mysql-test/r/having.result:
  test case
mysql-test/t/having.test:
  test case
sql/sql_select.cc:
  The fix is to use (table_map) 0 instead of used_tables in
  third argument for make_cond_for_table() function.
  It allows to extract elements which belong to sorted
  table and in addition elements which are independend
  subqueries.
This commit is contained in:
Sergey Glukhov
2011-04-22 11:20:55 +04:00
parent f3b024cafa
commit a5e8d9029b
3 changed files with 85 additions and 1 deletions
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22
mysql-test/r/having.result
View File

@ -545,4 +545,26 @@ FROM t1 JOIN t2 ON t2.f2 LIKE 'x'
HAVING field1 < 7;
field1
DROP TABLE t1,t2;
#
# Bug#48916 Server incorrectly processing HAVING clauses with an ORDER BY clause
#
CREATE TABLE t1 (f1 INT, f2 INT);
INSERT INTO t1 VALUES (1, 0), (2, 1), (3, 2);
CREATE TABLE t2 (f1 INT, f2 INT);
SELECT t1.f1
FROM t1
HAVING (3, 2) IN (SELECT f1, f2 FROM t2) AND t1.f1 >= 0
ORDER BY t1.f1;
f1
SELECT t1.f1
FROM t1
HAVING (3, 2) IN (SELECT 4, 2) AND t1.f1 >= 0
ORDER BY t1.f1;
f1
SELECT t1.f1
FROM t1
HAVING 2 IN (SELECT f2 FROM t2) AND t1.f1 >= 0
ORDER BY t1.f1;
f1
DROP TABLE t1,t2;
End of 5.1 tests

26
mysql-test/t/having.test
View File

@ -564,4 +564,30 @@ HAVING field1 < 7;
DROP TABLE t1,t2;
--echo #
--echo # Bug#48916 Server incorrectly processing HAVING clauses with an ORDER BY clause
--echo #
CREATE TABLE t1 (f1 INT, f2 INT);
INSERT INTO t1 VALUES (1, 0), (2, 1), (3, 2);
CREATE TABLE t2 (f1 INT, f2 INT);
SELECT t1.f1
FROM t1
HAVING (3, 2) IN (SELECT f1, f2 FROM t2) AND t1.f1 >= 0
ORDER BY t1.f1;
SELECT t1.f1
FROM t1
HAVING (3, 2) IN (SELECT 4, 2) AND t1.f1 >= 0
ORDER BY t1.f1;
SELECT t1.f1
FROM t1
HAVING 2 IN (SELECT f2 FROM t2) AND t1.f1 >= 0
ORDER BY t1.f1;
DROP TABLE t1,t2;
--echo End of 5.1 tests