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Fix for BUG#20188 "REPLACE or ON DUPLICATE KEY UPDATE in

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auto_increment breaks binlog":
if slave's table had a higher auto_increment counter than master's (even
though all rows of the two tables were identical), then in some cases,
REPLACE and INSERT ON DUPLICATE KEY UPDATE failed to replicate
statement-based (it inserted different values on slave from on master).
write_record() contained a "thd->next_insert_id=0" to force an adjustment
of thd->next_insert_id after the update or replacement. But it is this
assigment introduced indeterminism of the statement on the slave, thus
the bug. For ON DUPLICATE, we replace that assignment by a call to
handler::adjust_next_insert_id_after_explicit_value() which is deterministic
(does not depend on slave table's autoinc counter). For REPLACE, this
assignment can simply be removed (as REPLACE can't insert a number larger
than thd->next_insert_id).
We also move a too early restore_auto_increment() down to when we really know
that we can restore the value.
This commit is contained in:
guilhem@mysql.com
2006-07-05 14:41:35 +02:00
parent 8acb6eeb80
commit a43c4b0265
5 changed files with 157 additions and 24 deletions
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65
mysql-test/r/rpl_insert_id.result
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@ -132,3 +132,68 @@ id last_id
drop function bug15728;
drop function bug15728_insert;
drop table t1, t2;
create table t1 (n int primary key auto_increment not null,
b int, unique(b));
set sql_log_bin=0;
insert into t1 values(null,100);
replace into t1 values(null,50),(null,100),(null,150);
select * from t1 order by n;
n b
2 50
3 100
4 150
truncate table t1;
set sql_log_bin=1;
insert into t1 values(null,100);
select * from t1 order by n;
n b
1 100
insert into t1 values(null,200),(null,300);
delete from t1 where b <> 100;
select * from t1 order by n;
n b
1 100
replace into t1 values(null,100),(null,350);
select * from t1 order by n;
n b
2 100
3 350
select * from t1 order by n;
n b
2 100
3 350
insert into t1 values (NULL,400),(3,500),(NULL,600) on duplicate key UPDATE n=1000;
select * from t1 order by n;
n b
2 100
4 400
1000 350
1001 600
select * from t1 order by n;
n b
2 100
4 400
1000 350
1001 600
drop table t1;
create table t1 (n int primary key auto_increment not null,
b int, unique(b));
insert into t1 values(null,100);
select * from t1 order by n;
n b
1 100
insert into t1 values(null,200),(null,300);
delete from t1 where b <> 100;
select * from t1 order by n;
n b
1 100
insert into t1 values(null,100),(null,350) on duplicate key update n=2;
select * from t1 order by n;
n b
2 100
3 350
select * from t1 order by n;
n b
2 100
3 350
drop table t1;