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Fixed bug #25971: indexes on text columns were ignored when ref accesses

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were evaluated.
According to the new rules for string comparison partial indexes on text
columns can be used in the same cases when partial indexes on varchar
columns can be used.
This commit is contained in:
igor@olga.mysql.com
2007-02-14 22:06:41 -08:00
parent c84ee7079c
commit a2d4a042d0
7 changed files with 200 additions and 12 deletions
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148
mysql-test/r/select.result
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@ -3785,4 +3785,152 @@ case when 1 then cast(1111111111111111111 as unsigned) else 1 end c,
coalesce(cast(1111111111111111111 as unsigned), 1) co;
i c co
1111111111111111111 1111111111111111111 1111111111111111111
CREATE TABLE t1 (name varchar(255));
CREATE TABLE t2 (name varchar(255), n int, KEY (name(3)));
INSERT INTO t1 VALUES ('ccc'), ('bb'), ('cc '), ('aa '), ('aa');
INSERT INTO t2 VALUES ('bb',1), ('aa',2), ('cc ',3);
INSERT INTO t2 VALUES (concat('cc ', 0x06), 4);
INSERT INTO t2 VALUES ('cc',5), ('bb ',6), ('cc ',7);
SELECT * FROM t2;
name n
bb 1
aa 2
cc 3
cc  4
cc 5
bb 6
cc 7
SELECT * FROM t2 ORDER BY name;
name n
aa 2
bb 1
bb 6
cc  4
cc 3
cc 5
cc 7
SELECT name, LENGTH(name), n FROM t2 ORDER BY name;
name LENGTH(name) n
aa 2 2
bb 2 1
bb 3 6
cc  4 4
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT name, LENGTH(name), n FROM t2 WHERE name='cc ';
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 ref name name 6 const 3 Using where
SELECT name, LENGTH(name), n FROM t2 WHERE name='cc ';
name LENGTH(name) n
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%';
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 range name name 6 NULL 3 Using where
SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%';
name LENGTH(name) n
cc 5 3
cc  4 4
cc 2 5
cc 3 7
EXPLAIN SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%' ORDER BY name;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 range name name 6 NULL 3 Using where; Using filesort
SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%' ORDER BY name;
name LENGTH(name) n
cc  4 4
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT * FROM t1 LEFT JOIN t2 ON t1.name=t2.name;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 5
1 SIMPLE t2 ref name name 6 test.t1.name 2
SELECT * FROM t1 LEFT JOIN t2 ON t1.name=t2.name;
name name n
ccc NULL NULL
bb bb 1
bb bb 6
cc cc 3
cc cc 5
cc cc 7
aa aa 2
aa aa 2
DROP TABLE t1,t2;
CREATE TABLE t1 (name text);
CREATE TABLE t2 (name text, n int, KEY (name(3)));
INSERT INTO t1 VALUES ('ccc'), ('bb'), ('cc '), ('aa '), ('aa');
INSERT INTO t2 VALUES ('bb',1), ('aa',2), ('cc ',3);
INSERT INTO t2 VALUES (concat('cc ', 0x06), 4);
INSERT INTO t2 VALUES ('cc',5), ('bb ',6), ('cc ',7);
SELECT * FROM t2;
name n
bb 1
aa 2
cc 3
cc  4
cc 5
bb 6
cc 7
SELECT * FROM t2 ORDER BY name;
name n
aa 2
bb 1
bb 6
cc  4
cc 3
cc 5
cc 7
SELECT name, LENGTH(name), n FROM t2 ORDER BY name;
name LENGTH(name) n
aa 2 2
bb 2 1
bb 3 6
cc  4 4
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT name, LENGTH(name), n FROM t2 WHERE name='cc ';
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 ref name name 6 const 3 Using where
SELECT name, LENGTH(name), n FROM t2 WHERE name='cc ';
name LENGTH(name) n
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%';
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 range name name 6 NULL 3 Using where
SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%';
name LENGTH(name) n
cc 5 3
cc  4 4
cc 2 5
cc 3 7
EXPLAIN SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%' ORDER BY name;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t2 range name name 6 NULL 3 Using where; Using filesort
SELECT name , LENGTH(name), n FROM t2 WHERE name LIKE 'cc%' ORDER BY name;
name LENGTH(name) n
cc  4 4
cc 5 3
cc 2 5
cc 3 7
EXPLAIN SELECT * FROM t1 LEFT JOIN t2 ON t1.name=t2.name;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 5
1 SIMPLE t2 ref name name 6 test.t1.name 2
SELECT * FROM t1 LEFT JOIN t2 ON t1.name=t2.name;
name name n
ccc NULL NULL
bb bb 1
bb bb 6
cc cc 3
cc cc 5
cc cc 7
aa aa 2
aa aa 2
DROP TABLE t1,t2;
End of 5.0 tests