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mirror of https://github.com/MariaDB/server.git synced 2025-07-30 16:24:05 +03:00

MDEV-19421 Basic 3-way join queries are not parsed.

The parser returned a syntax error message for the queries with join
expressions like this t1 JOIN t2 [LEFT | RIGHT] JOIN t3 ON ... ON ... when
the second operand of the outer JOIN operation with ON clause was another
join expression with ON clause. In this expression the JOIN operator is
right-associative, i.e. expression has to be parsed as the expression
t1 JOIN (t2 [LEFT | RIGHT] JOIN t3 ON ... ) ON ...
Such join expressions are hard to parse because the outer JOIN is
left-associative if there is no ON clause for the first outer JOIN operator.
The patch implements the solution when the JOIN operator is always parsed
as right-associative and builds first the right-associative tree. If it
happens that there is no corresponding ON clause for this operator the
tree is converted to left-associative.

The idea of the solution was taken from the patch by Martin Hansson
"WL#8083: Fixed the join_table rule" from MySQL-8.0 code line.
As the grammar rules related to join expressions in MySQL-8.0 and
MariaDB-5.5+ are quite different MariaDB solution could not borrow
any code from the MySQL-8.0 solution.
This commit is contained in:
Igor Babaev
2019-06-30 13:16:12 -07:00
parent 8997f20f12
commit 8540fa83bb
8 changed files with 2078 additions and 28 deletions

View File

@ -1209,6 +1209,410 @@ CALL p1;
DROP PROCEDURE p1;
DROP TABLE t1,t2,t3,t4,t5;
--echo #
--echo # MDEV-19421: Embedding inner joins
--echo #
create table t1 (a int);
insert into t1 values (7), (5), (3);
create table s1 (b int);
insert into s1 values (7), (5), (3);
create table t2 (a int);
insert into t2 values (5), (1), (7);
create table s2 (b int);
insert into s2 values (5), (1), (7);
create table t3 (a int);
insert into t3 values (2), (7), (3);
create table t4 (a int);
insert into t4 values (4), (7), (9), (5);
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3 on t2.a=t3.a on t1.a=t2.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 left join t3 on t2.a=t3.a on t1.a=t2.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 right join t3 on t2.a=t3.a on t1.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3 using(a) using(a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 left join t3 using(a) using(a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 right join t3 using(a) using(a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3 on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 left join t3 on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 right join t3 on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3 on t1.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 left join t3 on t1.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 right join t3 on t1.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join (t2 join t3 on t2.a=t3.a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join (t2 left join t3 on t2.a=t3.a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join (t2 right join t3 on t2.a=t3.a);
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 left join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 right join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b, t2.a as t2_a, t3.a as t3_a
from s1 join t2 join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b, t2.a as t2_a, t3.a as t3_a
from s1 join t2 left join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b, t2.a as t2_a, t3.a as t3_a
from s1 join t2 right join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b, t2.a as t2_a, t3.a as t3_a
from (s1 join t2) right join t3 using(a);
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 natural join t3;
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 natural left join t3;
eval explain extended $q;
eval $q;
let $q=
select *
from s1 join t2 natural right join t3;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from t1 join t2 join t3
where t1.a=t2.a and t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 join t3 join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 left join t3 join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 left join t3 left join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 left join t3 right join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 right join t3 join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 right join t3 left join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 right join t3 right join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 join t3 join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 join t3 left join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 join t3 right join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t3.a as t3_a, t4.a as t4_a
from s1 join s2 join t3 join t4 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t3.a as t3_a, t4.a as t4_a
from s1 join s2 join t3 left join t4 using(a);
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t3.a as t3_a, t4.a as t4_a
from s1 join s2 join t3 right join t4 using(a);
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 join t3 on t2.a=t3.a join t4;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 left join t3 on t2.a=t3.a join t4;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 right join t3 on t2.a=t3.a join t4;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t2 join t3 using(a) join t4;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t2 left join t3 using(a) join t4;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t2 right join t3 using(a) join t4;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 on t1.a=t2.a join t3 join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 on t1.a=t2.a join t3 left join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 on t1.a=t2.a join t3 right join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 left join t2 on t1.a=t2.a join t3 join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 left join t2 on t1.a=t2.a join t3 left join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 left join t2 on t1.a=t2.a join t3 right join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 right join t2 on t1.a=t2.a join t3 join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 right join t2 on t1.a=t2.a join t3 left join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 right join t2 on t1.a=t2.a join t3 right join t4 on t3.a=t4.a;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t1 left join t2 on s1.b=t2.a join t3 join t4 on t4.a=s1.b;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t1 left join t2 on s1.b=t2.a join t3 left join t4 on t4.a=s1.b;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from s1 join t1 left join t2 on s1.b=t2.a join t3 right join t4 on t4.a=s1.b;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from s1 join s2 on s1.b=s2.b join t1 right join t2 on t1.a=t2.a join t3;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from s1 left join s2 on s1.b=s2.b join t1 right join t2 on t1.a=t2.a join t3;
eval explain extended $q;
eval $q;
let $q=
select s1.b as s1_b, s2.b as s2_b, t1.a as t1_a, t2.a as t2_a, t3.a as t3_a
from s1 right join s2 on s1.b=s2.b join t1 right join t2 on t1.a=t2.a join t3;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from t1 join t2 right join t3 right join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from (t1 join t2) right join t3 right join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
let $q=
select t1.a as t1_a, t2.a as t2_a, t3.a as t3_a, t4.a as t4_a
from (t1, t2) right join t3 right join t4 on t3.a=t4.a on t2.a=t3.a;
eval explain extended $q;
eval $q;
drop table t1,t2,t3,t4,s1,s2;
--echo #
--echo # End of MariaDB 5.5 tests
--echo #