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merge with 5.3
sql/sql_insert.cc: CREATE ... IF NOT EXISTS may do nothing, but it is still not a failure. don't forget to my_ok it. ****** CREATE ... IF NOT EXISTS may do nothing, but it is still not a failure. don't forget to my_ok it. sql/sql_table.cc: small cleanup ****** small cleanup
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@@ -90,6 +90,12 @@ extern const char _dig_vec_lower[];
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extern char *strmov_overlapp(char *dest, const char *src);
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#if defined(_lint) || defined(FORCE_INIT_OF_VARS)
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#define LINT_INIT_STRUCT(var) bzero(&var, sizeof(var)) /* No uninitialize-warning */
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#else
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#define LINT_INIT_STRUCT(var)
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#endif
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/* Prototypes for string functions */
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extern void bmove_upp(uchar *dst,const uchar *src,size_t len);
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@@ -215,75 +221,6 @@ struct st_mysql_const_unsigned_lex_string
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};
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typedef struct st_mysql_const_unsigned_lex_string LEX_CUSTRING;
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/* SPACE_INT is a word that contains only spaces */
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#if SIZEOF_INT == 4
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#define SPACE_INT 0x20202020
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#elif SIZEOF_INT == 8
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#define SPACE_INT 0x2020202020202020
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#else
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#error define the appropriate constant for a word full of spaces
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#endif
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/**
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Skip trailing space.
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On most systems reading memory in larger chunks (ideally equal to the size of
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the chinks that the machine physically reads from memory) causes fewer memory
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access loops and hence increased performance.
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This is why the 'int' type is used : it's closest to that (according to how
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it's defined in C).
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So when we determine the amount of whitespace at the end of a string we do
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the following :
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1. We divide the string into 3 zones :
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a) from the start of the string (__start) to the first multiple
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of sizeof(int) (__start_words)
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b) from the end of the string (__end) to the last multiple of sizeof(int)
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(__end_words)
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c) a zone that is aligned to sizeof(int) and can be safely accessed
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through an int *
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2. We start comparing backwards from (c) char-by-char. If all we find is
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space then we continue
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3. If there are elements in zone (b) we compare them as unsigned ints to a
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int mask (SPACE_INT) consisting of all spaces
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4. Finally we compare the remaining part (a) of the string char by char.
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This covers for the last non-space unsigned int from 3. (if any)
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This algorithm works well for relatively larger strings, but it will slow
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the things down for smaller strings (because of the additional calculations
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and checks compared to the naive method). Thus the barrier of length 20
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is added.
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@param ptr pointer to the input string
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@param len the length of the string
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@return the last non-space character
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*/
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static inline const uchar *skip_trailing_space(const uchar *ptr,size_t len)
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{
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const uchar *end= ptr + len;
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if (len > 20)
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{
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const uchar *end_words= (const uchar *)(intptr)
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(((ulonglong)(intptr)end) / SIZEOF_INT * SIZEOF_INT);
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const uchar *start_words= (const uchar *)(intptr)
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((((ulonglong)(intptr)ptr) + SIZEOF_INT - 1) / SIZEOF_INT * SIZEOF_INT);
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DBUG_ASSERT(((ulonglong)(intptr)ptr) >= SIZEOF_INT);
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if (end_words > ptr)
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{
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while (end > end_words && end[-1] == 0x20)
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end--;
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if (end[-1] == 0x20 && start_words < end_words)
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while (end > start_words && ((unsigned *)end)[-1] == SPACE_INT)
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end -= SIZEOF_INT;
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}
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}
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while (end > ptr && end[-1] == 0x20)
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end--;
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return (end);
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}
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static inline void lex_string_set(LEX_STRING *lex_str, const char *c_str)
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{
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lex_str->str= (char *) c_str;
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