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Fixed a cost estimation bug introduced into in the function best_access_path

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of the 5.3 code line after a merge with 5.2 on 2010-10-28
in order not to allow the cost to access a joined table to be equal
to 0 ever.

Expanded data sets for many test cases to get the same execution plans
as before.
This commit is contained in:
Igor Babaev
2011-09-30 18:55:02 -07:00
parent 42b928ca05
commit 715dc5f99d
61 changed files with 703 additions and 217 deletions
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16
mysql-test/r/subselect_mat_cost_bugs.result
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@@ -64,6 +64,12 @@ KEY c3 (c3,c2));
INSERT INTO t1 VALUES (10,7,8,'v','v');
INSERT INTO t1 VALUES (11,1,9,'r','r');
INSERT INTO t1 VALUES (12,5,9,'a','a');
INSERT INTO t1 VALUES (13,7,18,'v','v');
INSERT INTO t1 VALUES (14,1,19,'r','r');
INSERT INTO t1 VALUES (15,5,29,'a','a');
INSERT INTO t1 VALUES (17,7,38,'v','v');
INSERT INTO t1 VALUES (18,1,39,'r','r');
INSERT INTO t1 VALUES (19,5,49,'a','a');
create table t1a like t1;
insert into t1a select * from t1;
create table t1b like t1;
@@ -88,13 +94,13 @@ FROM (t1b JOIN t2 ON t2.c3 = t1b.c4) LEFT JOIN
t1a ON (t1a.c2 = t1b.pk AND 2)
WHERE t1.pk) ;
id select_type table type possible_keys key key_len ref rows filtered Extra
1 PRIMARY t1 ALL NULL NULL NULL NULL 3 100.00 Using where
2 DEPENDENT SUBQUERY t2 index c3 c3 9 NULL 2 100.00 Using index
2 DEPENDENT SUBQUERY t1b ALL NULL NULL NULL NULL 3 100.00 Using where; Using join buffer (flat, BNL join)
2 DEPENDENT SUBQUERY t1a ref c2 c2 5 test.t1b.pk 2 100.00 Using where
1 PRIMARY t1 ALL NULL NULL NULL NULL 9 100.00 Using where
2 DEPENDENT SUBQUERY t1b ALL NULL NULL NULL NULL 9 100.00
2 DEPENDENT SUBQUERY t1a ref c2 c2 5 test.t1b.pk 1 100.00 Using where
2 DEPENDENT SUBQUERY t2 index c3 c3 9 NULL 2 100.00 Using where; Using index; Using join buffer (flat, BNL join)
Warnings:
Note 1276 Field or reference 'test.t1.pk' of SELECT #2 was resolved in SELECT #1
Note 1003 select `test`.`t1`.`pk` AS `pk` from `test`.`t1` where <in_optimizer>(`test`.`t1`.`c1`,<exists>(select `test`.`t1a`.`c1` from `test`.`t1b` join `test`.`t2` left join `test`.`t1a` on((2 and (`test`.`t1a`.`c2` = `test`.`t1b`.`pk`))) where ((`test`.`t1`.`pk` <> 0) and (<cache>(`test`.`t1`.`c1`) = `test`.`t1a`.`c1`) and (`test`.`t1b`.`c4` = `test`.`t2`.`c3`))))
Note 1003 select `test`.`t1`.`pk` AS `pk` from `test`.`t1` where <in_optimizer>(`test`.`t1`.`c1`,<exists>(select `test`.`t1a`.`c1` from `test`.`t1b` join `test`.`t2` left join `test`.`t1a` on((2 and (`test`.`t1a`.`c2` = `test`.`t1b`.`pk`))) where ((`test`.`t1`.`pk` <> 0) and (<cache>(`test`.`t1`.`c1`) = `test`.`t1a`.`c1`) and (`test`.`t2`.`c3` = `test`.`t1b`.`c4`))))
SELECT pk
FROM t1
WHERE c1 IN