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BUG#17754

Added new syntax ALTER TABLE t1 REMOVE PARTITIONING,
changed semantics of ALTER TABLE t1 ENGINE=X; to not remove partitioning
Fix a number of mix engine bugs in partitioning


mysql-test/r/ndb_partition_key.result:
  Added a number of new test cases
mysql-test/r/partition.result:
  Added a number of new test cases
mysql-test/t/ndb_partition_key.test:
  Added a number of new test cases
mysql-test/t/partition.test:
  Added a number of new test cases
sql/lex.h:
  REMOVE and PARTITIONING added as keywords in parser
sql/sql_lex.h:
  Added flag to alter_info flag
sql/sql_partition.cc:
  Fixes for the new syntax, changes of the current semantics of the syntax.
  Fixes for errors in handling mixes of table handlers in partitioning syntax
  for ALTER TABLE
sql/sql_table.cc:
  Bug fix
sql/sql_yacc.yy:
  New syntax for REMOVE PARTITIONING
This commit is contained in:
unknown
2006-03-20 14:36:21 -05:00
parent ee9930bfa4
commit 51f70d9ff7
9 changed files with 454 additions and 41 deletions

View File

@@ -79,3 +79,49 @@ PARTITION BY KEY(a)
(PARTITION p0 ENGINE = NDB, PARTITION p1 ENGINE = NDB);
drop table t1;
#
# Bug #17754 Improper handling of removal of partitioning in ALTER TABLE
# Also added a number of general test cases in the same area
#
create table t1 (a int)
engine=ndb
partition by key(a)
(partition p0, partition p1);
show create table t1;
alter table t1 engine=heap;
show create table t1;
alter table t1 engine=ndb;
show create table t1;
alter table t1 engine=heap remove partitioning;
show create table t1;
alter table t1 engine=ndb
partition by key(a)
(partition p0, partition p1 engine = ndb);
show create table t1;
alter table t1
partition by key (a)
(partition p0 engine=ndb, partition p1 engine=ndb);
show create table t1;
alter table t1 remove partitioning;
show create table t1;
--error ER_MIX_HANDLER_ERROR
alter table t1
partition by key(a)
(partition p0 engine=ndb, partition p1);
alter table t1
engine=ndb
partition by key(a)
(partition p0 engine=ndb, partition p1 engine = ndb);
show create table t1;
drop table t1;