1
0
mirror of https://github.com/MariaDB/server.git synced 2025-07-30 16:24:05 +03:00

BUG#11766317: FIND_IN_SET won't work normaly after upgrade

from 5.1 to 5.5

(Former 59405)

In this bug, args[0] in an Item_func_find_in_set stored an 
Item_func_weekday that was constant. In 
Item_func_find_in_set::fix_length_and_dec(), args[0]->val_str() 
was called. Later, when Item_func_find_in_set::val_int() was 
called, args[0]->null_value was checked. However, the 
Item_func_weekday in args[0] had now been replaced with an 
Item_cache. No val_*() calls had been made to this Item_cache,
thus null_value was incorrectly 'true', resulting in missing 
rows in the result set.

enum_value gets a value in fix_length_and_dec() iff args[0]
is both constant and non-null. It is therefore unnecessary 
to check the null_value of args[0] in val_int().

An alternative fix would be to call args[0]->val_int() inside 
Item_func_find_in_set::val_int(). This would ensure
args[0]->null_value was set correctly (always false in this case), 
but that would have to be done for every record this const value 
is checked against.
This commit is contained in:
Jorgen Loland
2011-03-04 15:46:17 +01:00
parent e13c75a6d7
commit 40d72add32
3 changed files with 80 additions and 3 deletions

View File

@ -159,3 +159,45 @@ SELECT CONVERT( a USING latin1 ) FROM t2;
CONVERT( a USING latin1 )
DROP TABLE t1, t2;
#
# BUG#59405: FIND_IN_SET won't work normaly after upgrade from 5.1 to 5.5
#
CREATE TABLE t1(days set('1','2','3','4','5','6','7'));
INSERT INTO t1 VALUES('1,2,3,4,5,6,7'), (NULL), ('1,2,3,4,5,6,7');
SELECT * FROM t1 WHERE FIND_IN_SET(DAYOFWEEK(CURRENT_DATE()), days);
days
1,2,3,4,5,6,7
1,2,3,4,5,6,7
SELECT * FROM t1 WHERE FIND_IN_SET(DAYOFWEEK(CURRENT_DATE()), days) IS UNKNOWN;
days
NULL
SELECT * FROM t1 WHERE FIND_IN_SET(DAYOFWEEK(CURRENT_DATE()), NULL);
days
SELECT * FROM t1 WHERE FIND_IN_SET(DAYOFWEEK(CURRENT_DATE()), NULL) IS UNKNOWN;
days
1,2,3,4,5,6,7
NULL
1,2,3,4,5,6,7
SELECT * FROM t1 WHERE FIND_IN_SET(7, days);
days
1,2,3,4,5,6,7
1,2,3,4,5,6,7
SELECT * FROM t1 WHERE FIND_IN_SET(8, days);
days
SELECT * FROM t1 WHERE FIND_IN_SET(NULL, days);
days
SELECT * FROM t1 WHERE FIND_IN_SET(NULL, days) IS UNKNOWN;
days
1,2,3,4,5,6,7
NULL
1,2,3,4,5,6,7
SELECT * FROM t1 WHERE FIND_IN_SET(NULL, NULL);
days
SELECT * FROM t1 WHERE FIND_IN_SET(NULL, NULL) IS UNKNOWN;
days
1,2,3,4,5,6,7
NULL
1,2,3,4,5,6,7
DROP TABLE t1;