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Backport of Bug#27525 to mysql-next-mr

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------------------------------------------------------------
revno: 2572.2.1
revision-id: sp1r-davi@mysql.com/endora.local-20080227225948-16317
parent: sp1r-anozdrin/alik@quad.-20080226165712-10409
committer: davi@mysql.com/endora.local
timestamp: Wed 2008-02-27 19:59:48 -0300
message:
  Bug#27525 table not found when using multi-table-deletes with aliases over several databas
  Bug#30234 Unexpected behavior using DELETE with AS and USING

  The multi-delete statement has a documented limitation that
  cross-database multiple-table deletes using aliases are not
  supported because it fails to find the tables by alias if it
  belongs to a different database. The problem is that when
  building the list of tables to delete from, if a database
  name is not specified (maybe an alias) it defaults to the
  name of the current selected database, making impossible to
  to properly resolve tables by alias later. Another problem
  is a inconsistency of the multiple table delete syntax that
  permits ambiguities in a delete statement (aliases that refer
  to multiple different tables or vice-versa).

  The first step for a solution and proper implementation of
  the cross-databse multiple table delete is to get rid of any
  ambiguities in a multiple table statement. Currently, the parser
  is accepting multiple table delete statements that have no obvious
  meaning, such as:

  DELETE a1 FROM db1.t1 AS a1, db2.t2 AS a1;
  DELETE a1 AS a1 FROM db1.t1 AS a1, db2.t2 AS a1;

  The solution is to resolve the left part of a delete statement
  using the right part, if the a table on right has an alias,
  it must be referenced in the left using the given alias. Also,
  each table on the left side must match unambiguously only one
  table in the right side.
This commit is contained in:
Davi Arnaut
2009-11-10 16:48:46 -02:00
parent b53bb56724
commit 40c127eb44
9 changed files with 378 additions and 28 deletions
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2
mysql-test/suite/rpl/r/rpl_multi_delete2.result
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@@ -16,7 +16,7 @@ DELETE alias FROM a alias WHERE alias.i=1;
SELECT * FROM a;
i
insert into a values(2),(3);
delete a alias FROM a alias where alias.i=2;
delete alias FROM a alias where alias.i=2;
select * from a;
i
3