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Bug#27321: Wrong subquery result in a grouping select.
The Item_outer_ref class based on the Item_direct_ref class was always used to represent an outer field. But if the outer select is a grouping one and the outer field isn't under an aggregate function which is aggregated in that outer select an Item_ref object should be used to represent such a field. If the outer select in which the outer field is resolved isn't grouping then the Item_field class should be used to represent such a field. This logic also should be used for an outer field resolved through its alias name. Now the Item_field::fix_outer_field() uses Item_outer_field objects to represent aliased and non-aliased outer fields for grouping outer selects only. Now the fix_inner_refs() function chooses which class to use to access outer field - the Item_ref or the Item_direct_ref. An object of the chosen class substitutes the original field in the Item_outer_ref object. The direct_ref and the found_in_select_list fields were added to the Item_outer_ref class.
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@@ -432,7 +432,7 @@ alter table t1 add index idx(oref,ie);
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explain select oref, a, a in (select ie from t1 where oref=t2.oref) Z from t2;
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id select_type table type possible_keys key key_len ref rows Extra
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1 PRIMARY t2 ALL NULL NULL NULL NULL 7
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2 DEPENDENT SUBQUERY t1 ref_or_null idx idx 10 t2.oref,func 4 Using where; Using index; Full scan on NULL key
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2 DEPENDENT SUBQUERY t1 ref_or_null idx idx 10 test.t2.oref,func 4 Using where; Using index; Full scan on NULL key
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select oref, a, a in (select ie from t1 where oref=t2.oref) Z from t2;
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oref a Z
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ee NULL NULL
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@@ -457,7 +457,7 @@ group by grp having min(ie) > 1) Z
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from t2;
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id select_type table type possible_keys key key_len ref rows Extra
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1 PRIMARY t2 ALL NULL NULL NULL NULL 7
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2 DEPENDENT SUBQUERY t1 ref idx idx 5 t2.oref 2 Using where; Using temporary; Using filesort
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2 DEPENDENT SUBQUERY t1 ref idx idx 5 test.t2.oref 2 Using where; Using temporary; Using filesort
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select oref, a,
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a in (select min(ie) from t1 where oref=t2.oref
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group by grp having min(ie) > 1) Z
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@@ -661,12 +661,6 @@ SELECT * FROM t1 GROUP by t1.a
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HAVING (MAX(t1.b) > (SELECT MAX(t2.b) FROM t2 WHERE t2.c < t1.c
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HAVING MAX(t2.b+t1.a) < 10));
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a b c
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SELECT a, AVG(b), (SELECT t.c FROM t1 AS t WHERE t1.a=t.a AND t.b=AVG(t1.b))
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AS test FROM t1 GROUP BY a;
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a AVG(b) test
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1 4.0000 NULL
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2 2.0000 k
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3 2.5000 NULL
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SELECT a,b,c FROM t1 WHERE b in (9,3,4) ORDER BY b,c;
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a b c
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1 3 c
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