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Fix for BUG#9348: when computing union of two intervals set lower bound to

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minimum of lower bounds of two joined intervals.
This commit is contained in:
sergefp@mysql.com
2005-04-17 02:05:09 +04:00
parent 2b322f36d8
commit 2ef1963c91
3 changed files with 41 additions and 0 deletions
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19
mysql-test/r/range.result
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@ -577,3 +577,22 @@ id select_type table type possible_keys key key_len ref rows Extra
explain select * from t1 where a='aaa' collate latin1_german1_ci;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL a NULL NULL NULL 9 Using where
drop table t1;
CREATE TABLE t1 (
`CLIENT` char(3) character set latin1 collate latin1_bin NOT NULL default '000',
`ARG1` char(3) character set latin1 collate latin1_bin NOT NULL default '',
`ARG2` char(3) character set latin1 collate latin1_bin NOT NULL default '',
`FUNCTION` varchar(10) character set latin1 collate latin1_bin NOT NULL default '',
`FUNCTINT` int(11) NOT NULL default '0',
KEY `VERI_CLNT~2` (`ARG1`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO t1 VALUES ('000',' 0',' 0','Text 001',0), ('000',' 0',' 1','Text 002',0),
('000',' 1',' 2','Text 003',0), ('000',' 2',' 3','Text 004',0),
('001',' 3',' 0','Text 017',0);
SELECT count(*) FROM t1 WHERE CLIENT='000' AND (ARG1 != ' 1' OR ARG1 != ' 2');
count(*)
4
SELECT count(*) FROM t1 WHERE CLIENT='000' AND (ARG1 != ' 2' OR ARG1 != ' 1');
count(*)
4
drop table t1;