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Bug#46259: 5.0.83 -> 5.1.36, query doesn't work

The parser rule for expressions in a udf parameter list contains 
two hacks: 
First, the parser input stream is read verbatim, bypassing 
the lexer.
Second, the Item::name field is overwritten. If the argument to a
udf was a field, the field's name as seen by name resolution was
overwritten this way.
If the field name was quoted or escaped, it would appear as e.g. "`field`".
Fixed by not overwriting field names.

mysql-test/r/udf.result:
  Bug#46259: Test result.
mysql-test/t/udf.test:
  Bug#46259: Test case.
sql/sql_yacc.yy:
  Bug#46259: Fix.
This commit is contained in:
Martin Hansson
2009-09-07 11:57:22 +02:00
parent a00ba9ebea
commit 2cb3a131f4
3 changed files with 35 additions and 1 deletions

View File

@ -392,4 +392,20 @@ a
4
DROP FUNCTION sequence;
DROP TABLE t1,t2;
#
# Bug#46259: 5.0.83 -> 5.1.36, query doesn't work
#
CREATE TABLE t1 ( a INT );
INSERT INTO t1 VALUES (1), (2), (3);
SELECT IF( a = 1, a, a ) AS `b` FROM t1 ORDER BY field( `b` + 1, 1 );
b
1
2
3
SELECT IF( a = 1, a, a ) AS `b` FROM t1 ORDER BY field( `b`, 1 );
b
2
3
1
DROP TABLE t1;
End of 5.0 tests.

View File

@ -436,4 +436,16 @@ SELECT * FROM t2 WHERE a = sequence();
DROP FUNCTION sequence;
DROP TABLE t1,t2;
--echo #
--echo # Bug#46259: 5.0.83 -> 5.1.36, query doesn't work
--echo #
CREATE TABLE t1 ( a INT );
INSERT INTO t1 VALUES (1), (2), (3);
SELECT IF( a = 1, a, a ) AS `b` FROM t1 ORDER BY field( `b` + 1, 1 );
SELECT IF( a = 1, a, a ) AS `b` FROM t1 ORDER BY field( `b`, 1 );
DROP TABLE t1;
--echo End of 5.0 tests.